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3 years ago

10

He electron cloud is the predicted location for

1 answer:

DanielleElmas [232]3 years ago

7 0

Answer:

A) Electrons only

Explanation:

In quantum mechanics, "electron cloud" refers to the region of space where electrons can be found in an atom. In fact, in quantum mechanics, it is not possible to predict the exact position of the electrons, so there is a region where electrons have a certain probability to be found.

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You are vacationing in Iceland and exploring one of its famous volcanoes, Eyjafjallajokul, which erupted in April 2010. While si

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Igneous rock is the correct answer I hope this helps

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3 years ago

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The waves used by a microwave oven to cook food have a frequency of 2.45 gigahertz calculate the wavelength of this type of wave

fenix001 [56]

Electromagnetic wave bc I studied that early in the year

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3 years ago

Buoyant force is the net upward force that affects on the object in a fluid

Katarina [22]

Answer:True

Explanation:

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3 years ago

A plane has an airspeed of 142 m/s. A 30.0 m/s wind is blowing southward at the same time as the plane is flying. What must be t

const2013 [10]

Answer:

$\theta=12.19^{\circ}$

Explanation:

Given that

The speed of the airplane ,v= 142 m/s

The speed of the air ,u = 30 m/s

Lets take angle make by airplane from east direction towards north direction is θ .

Now by using diagram ,we can say that

$sin\theta =\dfrac{u}{v}$

Now by putting the values in the above equation we get

$sin\theta =\dfrac{30}{142}$

$sin\theta=0.21$

$\theta=12.19^{\circ}$

Therefore the angle will be 12.19° .

4 0

3 years ago

A bullet is fired horizontally at a height of 1.3 meters and a velocity of 950 m/s. How long was the bullet in the air?

seropon [69]

Answer:

<em>The bullet was 0.52 seconds in the air.</em>

Explanation:

<u>Horizontal Motion </u>

It occurs when an object is thrown horizontally with a speed v from a height h.

The object describes a curved path ruled exclusively by gravity until it hits the ground.

To calculate the time the object takes to hit the ground, we use the following equation:

$\displaystyle t=\sqrt{\frac{2y}{g}}$

Note it doesn't depend on the initial velocity but on the height.

The bullet is fired horizontally at h=1.3 m, thus:

$\displaystyle t=\sqrt{\frac{2\cdot 1.3}{9.8}}$

$\displaystyle t=\sqrt{\frac{2.6}{9.8}}$

t = 0.52 s

The bullet was 0.52 seconds in the air.

3 0

2 years ago