pls help If we multiply the mass of an object and the acceleration due to gravity, we find the downward force of the object whic
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5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).
We can calculate the moles of CaC₂O₄ obtained considering the following relationships.
- The molar mass of K₂C₂O₄ is 184.24 g/mol.
- The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.
5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
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Answer:- 1467 K
Solution:- It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.
Given:
V = 75.0 mL = 0.0750 L
P = 116.8 kPa
We know that, 101.325 kPa = 1 atm
So,
= 1.15 atm
R is universal gas constant and it's value is .
T = ?
Let's plug in the values in the equation and solve it for T.
0.08625 = 0.00005878(T)
T = 1467 K
So, the temperature of the light bulb would be 1467 K.