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-Dominant- [34]
3 years ago
6

Which pair of dispersed phases and dispersing media can never form a colloid?

Chemistry
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

Option B Liquid and Gas

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What is the trend in electronegativity for elements on the periodic table? It decreases across a period and increases down a gro
lilavasa [31]
It increases across a period and decreases down a group. A good way to remember this is that fluorine is the most electronegative atom, and it's to the top right of the table.
6 0
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What is the reaction that joins thousands of small, identical molecules to form one very long molecule?
34kurt
This is known as polymerisation 
8 0
2 years ago
Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how
Olegator [25]
C_{3} H_{8} + 5 O_{2} ---\ \textgreater \  3CO_{2}  +4H_{2}O    (-2012 \frac{kJ}{mol} )


3 mol                10 mol


C_{3}H_{8} is /excess /reactant

because 3 mol propane require 15 mol oxygen (by reaction)

5 mol oxygen ---1 mol propane, so

10 mol oxygen ---2 mol propane

Only 2 mole propane will be burned,

so 

2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off

Correct answer is number 4.



5 0
3 years ago
The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachlorid
stepladder [879]

Answer:

Final Answer: boiling point and high

Explanation:

3 0
3 years ago
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The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58
Umnica [9.8K]

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

5 0
3 years ago
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