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vivado [14]
3 years ago
9

Picture (a) Picture (a) Dipole-dipole forces London dispersion forces Ion-dipole forces Hydrogen bonding Request Answer Part B P

icture (b) Picture (b) Hydrogen bonding Dipole-dipole forces London dispersion forces Ion-dipole forces Request Answer Part C Picture (c) Picture (c) Ion-dipole forces Dipole-dipole forces Hydrogen bonding London dispersion forces Request Answer Part D Picture (d) Picture (d) Dipole-dipole forces Hydrogen bonding Ion-dipole forces London dispersion forces Request Answer Part E Predict which of the four interactions is the weakest Predict which of the four interactions is the weakest Forces on the picture (a). Forces on the picture (b). Forces on the picture (c). Forces on the picture (d).

Chemistry
1 answer:
Yuri [45]3 years ago
6 0

Answer:

(a) Hydrogen bonding

(b) Dispersion forces

(c) Ion-dipole forces

(d) Dipole-dipole forces

Ion-dipole forces (c) are the strongest of the 4 interactions while dispersion forces are the weakest (b).

Explanation:

The picture is missing but I think is the one that I'm uploading.

Picture (a)

HF is a polar molecule with a high difference in electronegativity between H and F. As a consequence, the force between HF molecules is Hydrogen bonding.

Picture (b)

In picture (b) we have F₂ molecules, which are nonpolar due to their atoms having the same electronegativity. The forces between nonpolar molecules are dispersion forces.

Picture (c)

Na⁺ is an ion and H₂O a dipole. Therefore, they experience ion-dipole forces.

Picture (d)

SO₂ molecules are polar, that is, they form dipoles and experience dipole-dipole forces.

Ion-dipole forces (c) are the strongest of the 4 interactions while dispersion forces are the weakest (b).

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If the relative errors of three quantities to be multiplied together are 0.009, 0.006 and 0.003, what is the relative error of t
Dima020 [189]

Answer: The relative error of the resulting quantity is 0.018.

Explanation: Relative error of the quantities when are multiplied together is usually less than or equal to the sum of each relative error. Mathematically, it is represented as

\delta x=\frac{\Delta x}{x}

According to the question,

Let us assume that the three quantities are r_1,r_2\text{ and }r_3

r=r_1\times r_2\times r_3

Taking log on both the sides, we get

log(r)=log(r_1\times r_2\times r_3)

log(r)=log(r_1)+log(r_2)+log(r_3)

Relative error is calculated by:

\frac{\delta r}{r}=\frac{\delta r_1}{r_1}+\frac{\delta r_2}{r_2}+\frac{\delta r_3}{r_3}

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4 0
4 years ago
2. Metric Conversion: Which units are equivalent (the same) as 75g? (Pick 3)
kogti [31]

Answer:

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7.5 dag

Explanation:

1 kg = 1000 g

So, 0.075 kg = (0.075 × 1000)g = 75 g

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So, 750 dg = (750 × 0.1) g = 75 g

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So, 7.5 dag = (7.5 × 10) g = 75 g

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3 years ago
Your teacher drinks a glass of water in the front of the classroom and claims, “this water could have been frozen in a glacier o
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Answer:

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Wind movement would then carry the clouds over great distances. These water droplets within a cloud will condense onto one another, causing the droplets to grow. When these water droplets become too heavy to remain suspended in the cloud, they will then either precipitate as rain or snow on land, rivers and oceans.

Over time, with continuous cycling and repetition of these processes, water melting from a glacier in Greenland will eventually make its way into the  Big Gunpowder Falls river which feeds the Loch Raven Reservoir in Baltimore and subsequently, the water will be supplied to our school's water fountain.

6 0
3 years ago
9. Thallium-208 has a half-life of 3.053 min. How long will it take for 120 g of it to decay
damaskus [11]

Answer:

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Radioactive isotopes decay exponentially in time, the mass of the isotope (m(t)), in grams, is described by the formula in time (t), in minutes:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

m_{o} - Initial mass of the isotope, in grams.

\tau - Time constant, in minutes.

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\tau = \frac{t_{1/2}}{\ln 2} (2)

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\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{3.053\,min}{\ln 2}

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t \approx 12.213\,min

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

4 0
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