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3 years ago

Why do you think some of the indicators used in experiment 2 were different than the ones used in experiment 1?

1 answer:

6 0

During selection of indicator. We choose an indicator which have pH range equivalent to the pH change of reaction to give better result and better observation.

So there are some different indicator are used in table 2 as compared to the table 1.

- Alizarin and phenolphthalein are basic indicator and their pH range is more than 8 so they are used in table 2

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A dental assistant is preparing to use a chemical that has a number 2 in a blue triangle on the chemical label. Before using the

Effectus [21]

Labels must clearly identify the chemical and include information on its hazards, plus instructions and information on its safe storage, handling, use, and disposal.

What does the information on the chemical label indicate?

The chemical label indicates the following information.

Product Identifier: The method used to identify the chemical (in the ingredient disclosure). On the label, include the complete chemical name or number that is used for the hazardous product. Both the label and SDS must have the same information. Abbreviations for chemicals are not accepted.

Signal Words: Assigned to a GHS hazard class and category, "Danger" or "Warning" are used to underline hazards and show the relative level of severity of the hazard.

Danger Statements: Typical expressions that are associated with a hazard class and category and that define the hazard's characteristics. On a label, there must be mention of every danger that applies.

Precautionary Statements: A term that describes actions that should be performed to reduce or eliminate negative effects brought on by exposure to or inappropriate storage of a substance.

Symbols (hazard pictograms): Convey information about environmental, physical, and health hazards that are categorized and allocated to a GHS hazard class.

Learn more about the chemical label here:

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5 0

2 years ago

What features did you use to classify igneous rocks as extrusive or intrusive ?

umka21 [38]

Answer: Igneous rocks may be simply classified according to their chemical/mineral composition as felsic, intermediate, mafic, and ultramafic, and by texture or grain size: intrusive rocks are course grained (all crystals are visible to the naked eye) while extrusive rocks may be fine-grained (microscopic crystals) or glass.

Explanation: Hope this helped! :)

6 0

3 years ago

Read 2 more answers

How many moles are in 7.2x10^15 atoms of Pb?

fiasKO [112]

<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

6 0

3 years ago

Given that cao(s) + h2o(l) → ca(oh)2(s), δh°rxn = –64.8 kj/mol, how many grams of cao must react in order to liberate 525 kj of

USPshnik [31]

Answer:

454.3 g.

Explanation:

From the given data:

1.0 mol of CaO liberates → – 64.8 kJ.

??? mol of CaO liberates → - 525 kJ.

∴ The no. of moles needed = (1.0 mol)(- 525 kJ)/(- 64.8 kJ) = 8.1 mol.

<em>∴ The no. of grams of CaO needed = no. of moles x molar mass</em> = (8.1 mol)(56.077 g/mol) = <em>454.3 g.</em>

8 0

3 years ago

True or false. Large covalent molecules with the same molecular formula or more likely to have identical angles between orbitals

Alexeev081 [22]

True, because the large covalent molecules would combine with the others

6 0

4 years ago