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Anna [14]
2 years ago
13

Which of the following is a chemical change?

Chemistry
2 answers:
Scorpion4ik [409]2 years ago
8 0
Answer: D, splitting water into hydrogen and oxygen is a chemical change.
krok68 [10]2 years ago
5 0
Answer: D


Explanation: Water splitting is the chemical reaction in which water is broken down into oxygen and hydrogen
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How does the vegetation surface type affect the amount of runoff
maxonik [38]

Answer:

<em>The type of vegetation a surface does affect the </em><em>water coming from above to sink in or runoff. </em>

Explanation:

This is how the vegetation affects the runoff:-

The leaves and stems present in the vegetation do not let the water fall directly on the soil and makes the process rather slow which makes the water to get to the ground slowly and sink in properly inside the soil rather than running off.

If the vegetation present is dense with  there was being hairy then also the water would not run out and will get absorbed by the roots letting the soil intact

5 0
3 years ago
Ethanol had a boiling point of 78.4°C. Propane has a boiling point of -42°C. Suggest why.​
Gwar [14]

Answer:

Chemical compounds all have different melting points.

Explanation:

chemical compounds all have different freezing and boiling points. Different chemical compounds means they will have different chemical structures.

7 0
3 years ago
6th grade science . :((
Nadusha1986 [10]

Answer:

C- private

Explanation:

This event seems to be exclusive. That is why it is private.

3 0
3 years ago
If volumes are additive and 253 mL of 0.19 M potassium bromide is mixed with 441 mL of a potassium dichromate solution to give a
Alexxx [7]

Answer:

The concentration of the Potassium Dichromate solution is 0.611 M

Explanation:

First of all, we need to understand that in the final solution we'll have potassium ions coming from KBr and also K2Cr2O7, so we state the dissociation equations of both compounds:

KBr (aq) → K+ (aq) + Br- (aq)

K2Cr2O7 (aq) → 2K+ (aq) + Cr2O7 2- (aq)

According to these balanced equations when 1 mole of KBr dissociates, it generates 1 mole of potassium ions. Following the same thought, when 1 mole of K2Cr2O7 dissociates, we obtain 2 moles of potassium ions instead.

Having said that, we calculate the moles of potassium ions coming from the KBr solution:

0.19 M KBr: this means that we have 0.19 moles of KBr in 1000 mL solution. So:

1000 mL solution ----- 0.19 moles of KBr

253 mL solution ----- x = 0.04807 moles of KBr

As we said before, 1 mole of KBr will contribute with 1 mole of K+, so at the moment we have 0.04807 moles of K+.

Now, we are told that the final concentration of K+ is 0.846 M. This means we have 0.846 moles of K+ in 1000 mL solution. Considering that volumes are additive, we calculate the amount of K+ moles we have in the final volume solution (441 mL + 253 mL = 694 mL):

1000 mL solution ----- 0.846 moles K+

694 mL solution ----- x = 0.587124 moles K+

This is the final quantity of potassium ion moles we have present once we mixed the KBr and K2Cr2O7 solutions. Because we already know the amount of K+ moles that were added with the KBr solution (0.04807 moles), we can calculate the contribution corresponding to K2Cr2O7:

0.587124 final K+ moles - 0.04807 K+ moles from KBr = 0.539054 K+ moles from K2Cr2O7

If we go back and take a look a the chemical reactions, we can see that 1 mole of K2Cr2O7 dissociates into 2 moles of K+ ions, so:

2 K+ moles ----- 1 K2Cr2O7 mole

0.539054 K+ moles ---- x = 0.269527 K2Cr2O7 moles

Now this quantity of potassium dichromate moles came from the respective  solution, that is 441 mL, so we calculate the amount of them that would be present in 1000 mL to determine de molar concentration:

441 mL ----- 0.269527 K2Cr2O7 moles

1000 mL ----- x = 0.6112 K2Cr2O7 moles = 0.6112 M

6 0
3 years ago
If you are calculating the grams to mL ratio, you are trying to find the object’s…
Alex

Answer:

Density

Explanation:

The ratio of mass to the volume of an object is called its density. Unit of mass is grams and that of volume is mL.

Density = mass/volume

\text{Density}=\dfrac{\text{grams}}{\text{mL}}\\\\=\text{grams/mL}

If you are calculating the grams to mL ratio, it means that we are trying to find the object's density.

4 0
3 years ago
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