Answer:
B. A few positive particles bounced back because they were pushed away from the positive center.
Explanation:
The result of the experiment conducted by Rutherford shows that a few positive particles bounced back because they were pushed away from the positive center.
This is the central theme of Rutherford's experiment on a thin gold foil.
- In 1911, Rutherford performed the gold foil experiment that gave the modeling of the atomic structure a great boost.
- He bombarded a thin gold foil with alpha particles.
- He discovered that most of the alpha particles passed through the foil while a few of them were deflected back.
- This led him to postulate that an atom has a small positively charged center where nearly all the mass is concentrated.
I suppose that the question ask the following:
What is the mass of a sample, composed of C₃H₅N₃O₉ molecule, that contains 100 g carbon?
First we calculate the molecular mass of our molecule C₃H₅N₃O₉.
molecular mass = 12 × 3 + 1 × 5 + 14 × 3 + 16 × 9 = 227 g/mol
Now we devise the following reasoning:
if 227 g of our molecule contains 27 g of carbon
then X g of our molecule contains 100 g carbon
X = (100 × 227) / 27 = 840.7 g
Answer:
both are a number group of 12
Explanation:
dozen=12