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skelet666 [1.2K]
3 years ago
6

Based on the molar masses, how can you tell that an equation is balanced?

Chemistry
2 answers:
Ilya [14]3 years ago
7 0
When you work with molar mass, you solve for the quantity of ''Moles'' within the substance by converting Mass. The way you can tell the equation is balanced would be by knowing whether the moles were equivalent on both sides or not. Therefore, if they are equal, it is balanced considering you have the same amount of moles on each side of the equation.
Rashid [163]3 years ago
5 0

Explanation :

According to the law of conservation of mass, the mass of reactant must be equal to the mass of product. That means mass remains conserved.

Based on the molar masses, we can tell that an equation is balanced or not.

If the sum of the molar mass of reactant side will be equal to the sum of the molar mass of product side then we can tell that an equation is balanced otherwise an equation is not balanced.

For example : 2Na+2H_2O\rightarrow 2NaOH+H_2

Now we have to check that this reaction is balanced or not.

As per law of conservation of mass,

Sum of molar mass of reactant = Sum of molar mass of product

2Na+2H_2O=2NaOH+H_2

The molar mass of sodium(Na), hydrogen(H) and oxygen(O) are 23, 1 and 16 g/mole respectively.

2(23)+2(2\times 1+16)=2(23+16+1)+2(1)

82=82

The mass of reactant side is equal to the product side that means this equation is balanced.

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3 years ago
a one gram sample of hematite up more space than a one gram sample of malachite. what mineral characteristic does this refer to
Gwar [14]
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7 0
3 years ago
When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2
Arlecino [84]

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide  =\dfrac{70.4 \ g}{121.14 \ g/mol}

= 0.58 mole

The molality = \dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent  }

= \dfrac{0.58 }{0.85 }

= 0.6837

Using the formula:

\mathbf {dT  = l   \times  k_f  \times m}

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf ×  0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = \dfrac{70.4 \ g}{53.491 \  g /mol}

= 1.316 mol

The molality = \dfrac{1.316 \ mol}{0.85 \ kg}

= 1.5484

Thus;

the above kf value is used in determining the  Van't Hoff factor for  NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

l = \dfrac{9.9}{3.949 \times 1.5484 \ m}

l = 1.62

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2 years ago
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Answer:

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Explanation:

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Hence, weight of mass 8Kg wil transfer heat a fast rate.

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