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3 years ago

How many moles are in 2.0 grams of FeO

Chemistry

2 answers:

timurjin [86]3 years ago

7 0

Answer: 0.027837938656318

Explanation: Because 1 grams FeO is equal to 0.013918969328159 mole.

Natali [406]3 years ago

4 0

Answer:

.027798 moles

Explanation:

Molar mass of Iron (II) Oxide.

Molar mass of iron is 55.847

Molar mass of Oxygen is 15.9994

Add the two.

55.947 + 15.9994 = 71.9464

2 (grams) / 71.9464 (molar mass) = .027798 moles

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When 2.3 × 10^3 g of CaCO3 are heated, the actual yield of CaO is 1.09 × 10^3g. What is

iren [92.7K]

The percent yield : 4. 84.58%

<h3>Further explanation</h3>

Reaction

CaCO₃ ⇄ CaO+CO₂

mass CaCO₃ = 2.3 × 10³ g

mol CaCO₃ (MW=100.0869 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{2.3\times 10^3}{100,0869}\\\\mol=22.98$

From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98

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$\tt mass=mol\times MW\\\\mass=22.98\times 56,0774\\\\mass=1288.659~g$

The percent yield :

$\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{1090}{1288.659}\times 100\%\\\\\5yield=84.58\%$

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3 years ago

How many atoms of hydrogen combine with one carbon atom to form methane

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Answer:four hydrogen atoms

Explanation:

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3 years ago

plz help me asap and find the surface area here are the numbers 8 10 10 5 5 10 10. here is the other one 10 10 12 8 12 10 10 8

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3 years ago

Read 2 more answers

In a first-order decomposition reaction, 50.0% of a compound decomposes in 10.5 min.

mihalych1998 [28]

In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol $t_{1/2}$ .

(a) For first order reaction, rate constant and half life time are related to each other as follows:

$k=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{10.5 min}=0.066 min^{-1}$

Thus, rate constant of the reaction is $0.066 min^{-1}$ .

(b) Rate equation for first order reaction is as follows:

$k=\frac{2.303}{t_{1/2}}log\frac{[A_{0}]}{[A_{t}]}$

now, 75% of the compound is decomposed, if initial concentration $[A_{0} ]$ is 100 then concentration at time t $[A_{t} ]$ will be 100-75=25.

Putting the values,

$0.066 min^{-1}=\frac{2.303}{t}log\frac{100}{25}=\frac{2.303}{t}(0.6020)$

On rearranging,

$t=\frac{2.303\times 0.6020}{0.066 min^{-1}}=21 min$

Thus, time required for 75% decomposition is 21 min.

8 0

4 years ago