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antiseptic1488 [7]
2 years ago
13

PLEASE HELP ME ASAP!!! THIS IS DUE UNTIL 1:30 PM!!! Tell how many Elements are in this compound and tell what the Elements are.

NaClOFeCoH
Chemistry
2 answers:
il63 [147K]2 years ago
5 0

Answer:

6 elements

Explanation:

each element Na, Cl, O, Fe, Co, H

Nuetrik [128]2 years ago
4 0

Answer: 13

Explanation: I got it right

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Nitrogen and hydrogen combine to form ammonia.
zhenek [66]

The balanced chemical equation for the formation ammonia is

    N2(g) + 3H2(g)  ----> 2NH3(g)  .        

The balanced chemical equations explains that the same number of each element exist as reactants and products.  The coefficients in a balanced equation must be the simplest whole number ratio. Mass is always conserved in chemical reactions.

For the formation of ammonia, the chemical equation is

     N2(g) + H2(g)  ----> NH3(g)

Balancing the chemical reaction, we can write,

  N2(g) + 3H2(g)  ----> 2NH3(g)  .  

This equation shows two nitrogen entering the reaction together and two hydrogens entering the reaction together. Since NH3 is multiplied by a coefficient of 2 there are now 2 nitrogen and 6 hydrogens. The 6 hydrogens come from the 2 multiplied by the subscript of 3. This is the balanced chemical reaction.

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8 months ago
Calculate the relative formula mass for KMnO4
GarryVolchara [31]

Explanation:

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2 years ago
Picture a neutral P atom. This neutral atom will have
aleksandr82 [10.1K]

Answer:

It will have 5 valence electrons as its in group 5.

The atom will gain as its closer to the full configuration 8.

The charge will be 3- as it will gain 3 electrons.

3 0
2 years ago
How to go this problem
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4 0
3 years ago
Determine the theoretical maximum moles of ethyl acetate, , that could be produced in this experiment. The reactant, acetic acid
kherson [118]

Answer:

0.1832 moles of ethyl acetate (C_{4}H_{8}O_{2})

Explanation:

1. Find the balanced chemical equation:

In the production of ethyl acetate, the acetic acid CH_{3}COOH reacts with ethanol to produce ethyl acetate C_{4}H_{8}O_{2} and water, that is:

CH_{3}COOH+C_{2}H_{5}OH=C_{4}H_{8}O_{2}+H_{2}O

2. Find the theoretical maximum moles of ethyl acetate C_{4}H_{8}O_{2}:

As the problem says that the acetic acid CH_{3}COOH is the limiting reagent, use stoichiometry to find the moles of ethyl acetate produced:

11gCH_{3}COOH*\frac{1molCH_{3}COOH}{60.05gCH_{3}COOH}*\frac{1molC_{4}H_{8}O_{2}}{1molCH_{3}COOH}=0.1832molesC_{4}H_{8}O_{2}

4 0
3 years ago
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