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nexus9112 [7]
3 years ago
7

The complete orbital notation diagram of an atom is shown.

Chemistry
1 answer:
Elan Coil [88]3 years ago
5 0

values of the quantum numbers: -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6

location of the electron: In the 7th energy level away from the nucleus.

Explanation:

From the description of the problem, the magnetic number is given is as -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and the electron is located in the 7th energy level away from the nucleus. Basically, the problem is testing for the understanding of the principal quantum numbers which gives the location of electrons and the magnetic quantum number that shows the spatial orientation of the orbitals.

           The orbital designation of the describe electron is 7d

  1. Magnetic quantum number is limited by the azimuthal quantum number which is the quantum number describing the possible shapes. The azimuthal is given as L= n-1. "n" is the principal quantum number which is 7. Therefore L is 6 and the magnetic quantum numbers are -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6
  2. The position of the electron is given by the principal quantum number which represents the main energy level in which the orbital is located or the average distance from the nucleus. Here it is 7.

Learn more:

brainly.com/question/9288609

#learnwithBrainly

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The buildup of sediment where a river empties into a slow-moving or nonmoving body of water is known as a/an
777dan777 [17]

The buildup of sediment in which a river empties right into a slow-transferring or non transferring frame of water is referred to as a Delta.

<h3>What is Delta ?</h3>

Deltas are wetlands that shape as rivers empty their water and sediment into some other frame of water, together with an ocean, lake, or some other river.

A form of soil made nearly completely of windblown sediment is referred to as Loess.

The natural count number in soil comes from decaying flora and animals and their waste products.

Clay, that's made of tiny debris and drains water very poorly, is one of the essential additives of soil.

A form of soil referred to as peat is maximum probably to shape in a/an Coastal surroundings in Tropical placing.

Water enables withinside the improvement of soil with the aid of using carrying Mineral and vitamins from higher layers to decrease layers.

The Richness of nutrients from soil is not unusualplace in moist environments, like rain forests.

Quartz-wealthy determine cloth results in the improvement of Sandy soils.

The layers of soil composed specifically of natural count number are referred to as the O and A horizon.

A layer of soil wherein clay, iron, and different factors from the overlying soil accumulates is referred to as the B horizon, or subsoil.

  • Delta is stated to be a frame of sediments deposited whilst a river flows into a status water, together with the ocean or a lake.

  • Loess are wind blown deposits of silts and clay composed of quartz, feldspar and different minerals . Loess dominantly have excessive porosity.

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6 0
2 years ago
Correct name for #10 please
ira [324]

Answer:

CH₃CH(CH₃)CH(C₃H₇)CH₂CH(CH₃)₂:

4-isopropyl-2-methylpentane.

Explanation:

Step One: Draw the structure formula of this compound. Parentheses in the formula indicate substitute groups that are connected to the carbon atom to the left.

For example, the first (CH₃) indicates that the second carbon atom from the left is connected to:

  • the CH₃- on the left-hand side,
  • the -CH(C₃H₇)CH₂CH(CH₃)₂ on the right-hand side,
  • a hydrogen atom, and
  • an additional CH₃- group that replaced one hydrogen atom.

Each carbon atom in this compound is connected to four other atoms. All bonds between carbon atoms are single bonds.

The C₃H₇ in the second pair of parentheses is the condensed form of CH₃CH₂CH₂-. See the first sketch attached. Groups in parentheses are highlighted.

Step Two: Find the carbon backbone. The backbone of a hydrocarbon is the longest chain of carbon atoms that runs through the compound. See the second sketch attached. The backbone of this compound consists of seven carbon atoms and is highlighted in green. The name for this backbone shall be heptane.

Step Three: Identify and name the substitute groups.

The two substitute groups are circled in blue in the second sketch.

  • The one on the right -CH₃ is a methyl group.
  • The one on the left is branched. \begin{aligned}\text{CH}_3-&\text{CH}-\text{CH}_3\\[-0.5em]&\;|\end{aligned} This group can be formed by removing one hydrogen from the central carbon atom in propane. The name for this group is isopropyl.

Step Four: Number the atoms.

Isopropyl shall be placed before methyl. Start from the right end to minimize the index number on all substitute groups. The methyl group is on carbon number two and the isopropyl group on carbon number four. Hence the name:

4-isopropyl-2-methylheptane.

5 0
3 years ago
calculate the amount of current that must flow for 50 minutes to a solution of silver trioxonitrate (V) solution to deposit 2 mo
mamaluj [8]

Explanation:

i found this the question is different but I think the situation is same

5 0
2 years ago
How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with
konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = a=31 cm^2

Thickness of the gold plating  = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3

Density of the gold = d=19.3 g/cm^3

m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g

Moles of gold = \frac{29.915 g}{197 g/mol}=0.152 mol

Au^{3+}+3e^-\rightarrow Au

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

\frac{3}{1}\times 0.152 mol=0.456 mol of electrons

Number of electrons = N =0.456\times \times 6.022\times 10^{23}

Charge on single electron = q=1.6\times 10^{-19} C

Total charge required = Q

Q=N\times q

Amount of current passes = I = 8 Ampere

Duration of time  = T

I=\frac{Q}{T}

T=\frac{N\times q}{I}

=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0
3 years ago
In a 0.737 m solution, a weak acid is 12.5% dissociated. calculate ka of the acid.
r-ruslan [8.4K]
Hello! Let me try to answer this :)

Thanks and please correct if there are any mistakes ^ ^

8 0
3 years ago
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