Answer:
Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction.
Explanation:
The CO appears twice hence in he intermediate reaction it only forms path of the enabling reagents and it further reacts to form the final product. Accounting for the CO in the intermediate reaction that undergoes further reaction will impact on the stoichiometry of the reaction.
Answer:
In the center is the eye, with nearly clear skies, surrounded by the violent eyewall, with the strongest winds and very heavy rain.
Explanation:
The number of moles that are contained in the given mass of propane (
is 1.7143 moles.
<u>Given the following data:</u>
- Mass of propane = 75.6 grams.
<u>Scientific data:</u>
- The molar mass of propane = 44.1 g/mol.
To calculate the number of moles that are contained in the given mass of propane (
):
<h3>How to calculate the moles of a compound.</h3>
In this exercise, you're required to determine the number of moles of propane that are contained in the given sample:
Mathematically, the number of moles contained in a chemical compound is given by this formula:

Substituting the given parameters into the formula, we have;

Number of moles = 1.7143 moles.
Read more on number of moles here: brainly.com/question/3173452
Answer:
Mass = 1274 .64 g it would be option C if it is converted into kilogram
1274 .64 / 1000 = 1.27 Kg
Explanation:
Given data:
Number of moles of C₂₀H₄₂ = 4.52 mol
Molar mass of carbon = 12 g/mol
Molar mass of hydrogen = 1.0 g/mol
Mass of C₂₀H₄₂ = ?
Solution:
Number of moles = mass / molar mass
Molar mass = 20× 12 + 42× 1.0 = 282 g/mol
Now we will put the values in formula:
Number of moles = mass / molar mass
4.52 mol = mass / 282 g /mol
Mass = 4.52 mol × 282 g/mol
Mass = 1274 .64 g