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Allisa [31]
3 years ago
8

The path urine takes after it is formed until it leaves the body is the urethra, urinary bladder, and finally the ureter. True F

alse
Chemistry
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer:

False

Explanation:

The urine is produced in the kidneys, each one of the kidneys is connected to a ureter.  The ureter is a tube that propels the excreted urine to the urinary bladder. The urinary bladder is a deposit for the urine, here is collected and stored before disposal. After the urinary bladder, the urine goes through the urethra, which is a tube, to exit the body.

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When you remove energy from a substance there will be a *
stira [4]

Answer:

b, decrease in movement of the molecules

Explanation:

removing the energy will begin making the molecules lock up and stop moving due to the loss of energy.

hope this helped

3 0
3 years ago
What is the total mass of solute in 1000. grams of a solution having a concentration of 5 parts per million?
Art [367]

50 grams or 50,000 mili grams  is the mass of solute in 1000 grams of a solution having a concentration of 5 parts per million.

Explanation:

Total mass of solution = 1000 grams or 1000 ml since 1 gram = 1 ml

concentration is 5 parts per million ( 5 mg in 1000 ml solution or 0.005 gram in 1000 ml)

the formula used for parts per million:

parts per million = \frac{mass of solute (mg)}{volume of solution}

putting the values in the equation:

parts per million = \frac{mass of solute}{volume of solvent}

0.005 x 1000 = mass of solute

50 grams= mass of solute

converting this into mg

50,000 mg. is the total mass of solute in 5ppm of 1000 ml solution.

4 0
3 years ago
.
Natasha_Volkova [10]

Answer:

(C) through the atmosphere

Explanation:

6 0
2 years ago
Read 2 more answers
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
A.<br> B.<br> C.<br> D.<br><br> what could be the correct answer? Help me please
AlladinOne [14]

Answer:

A

Explanation:

5 0
3 years ago
Read 2 more answers
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