This change in pressure is caused by changes in air density, and air density is related to temperature.
That photon's energy is equal to Planck 's constant, multiplied by the light frequency, h is always 6.63* 10^ -34 Joule seconds and the frequency is 6* 10^ 14 Hz.
<span>CH</span>₃<span>CH</span>₂<span>COOH + H</span>₂<span>O </span>↔ <span> CH</span>₃<span>CH</span>₂<span>COO</span>⁻<span> + H</span>₃<span>O</span>⁺<span>
</span>
pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
= 4.2 - (0.5 * (-log 1.34 x 10⁻⁵)) = 1.76
pCa = 3.53
Ca = antilog - 3.52 = 3 x 10⁻⁴
where Ca is the acid concentration
Answer:
first at start Aarau so I just way we Z
1×10^-4 = 0,0001M
pH = -log[H+]
pH = -log0,0001
pH = 4
