Answer:
v = 10 cm³
Explanation:
Given data:
Mass of sample = 80 g
Density of sample = 8 g/cm³
Volume of sample = ?
Solution:
We will calculate the volume by rearranging the density formula,
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
d =m/v
d = density
m =mass
v = m/d
Now we will put the values in formula,
v = 80 g / 8 g/cm³
v = 10 cm³
Answer:
1.The electrode on the right is positive
2. 0.058V
Explanation:
The above cell is a concentration cell.
A concentration cell is an electrolytic cell that is made of two half-cells with the same electrodes, but differs in concentrations of the solutions. A concentration cell functions by diluting the more concentrated solution and concentrating the more dilute solution, creating a voltage as the cell reaches an equilibrium thereby transferring the electrons from the cell with the lower concentration to the cell with the higher concentration.
In the above cell, electrons flow from the left electrode (less concentrated) to the right electrode (more concentrated). Therefore, the right electrode is the positive electrode (cathode).
Part 2: Please, see the attachment below for the calculations.
Answer:
its a chemical formula, it has numbers and symbols
The sample must be sufficiently soluble (fig. 2) to yield an NMR spectrum. For 1H and 1H observed NMR, it is recommended to dissolve between 2 and 10 mg in between 0.6 and 1 mL of solvent so that the sample depth is at least 4.5 cm in the tube (fig. 3).
Answer:
The formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Explanation:
Iron (ii) ions, Fe²⁺ have a positive charge of +2. Chromate ions, CrO₄²⁻, on the other hand have a positive charge of -2. When iron (ii) ions and chromate ions combine two form a compound, each ion will contribute a mole of ion towards the formation of the compound. This is in line with the idea that a compound carries no charge. The positive charge (+2) of the iron (ii) ions are balanced by the negative charge of the chromate ions as shown mathematically as follows;
+2 + (-2) = 0; i.e. Fe²⁺ + CrO₄²⁻ = FeCrO₄
Therefore, the formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
