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3 years ago

Show your work and include answer with units. How many atoms in 55 grams of magnesium

Chemistry

1 answer:

Georgia [21]3 years ago

8 0

Answer:

1.38 x $10^{24}$ atoms

Explanation:

To get grams to atoms/molecules/particles we need to first convert grams > moles > atoms. This also applies in the other direction, where you have moles as that stepping stone.

Some key information we need:

Magnesium's molar mass= 24g/mol

Avogadro's Number= 6.022 x $10^{23}$ atoms

Where there is 1 mol per 6.022 x $10^{23}$ atoms

*This maybe be something you want to memorize.

Grams to moles using molar mass , then to atoms using avogadro's number.

55g Mg x $\frac{1 mol}{24g/mol}$ x $\frac{6.022 x 10^{23} atoms }{1 mol}$ = 1.38 x $10^{24}$ atoms

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Calculate the solubility of nitrogen in water at an atmospheric pressure of 0.480 atm (a typical value at high altitude). Atmosp

maria [59]

Answer : The solubility of nitrogen in water at an atmospheric pressure will be, $2.5125\times 10^{-4}mole/L$

Explanation :

First we have to calculate the partial pressure of nitrogen.

Formula used :

$p_{N_2}=X_{N_2}\times P_{atm}$

where,

$p_{N_2}$ = partial pressure of nitrogen = ?

$X_{N_2}$ = mole fraction of nitrogen = $7.81\times 10^{-1}$

$p_{atm}$ = atmospheric pressure = 0.480 atm

Now put all the given values in the above formula, we get :

$p_{N_2}=7.81\times 10^{-1}\times 0.480 atm$

$p_{N_2}=0.375atm$

Now we have to calculate the solubility of nitrogen in water.

Formula used :

$s_{N_2}=p_{N_2}\times K_H$

where,

$p_{N_2}$ = partial pressure of nitrogen = 0.375 atm

$s_{N_2}$ = solubility of nitrogen in water = ?

$K_H$ = Henry's constant = $6.70\times 10^{-4}mole/L.atm$

Now put all the given values in the above formula, we get :

$s_{N_2}=0.375atm\times 6.70\times 10^{-4}mole/L.atm$

$s_{N_2}=2.5125\times 10^{-4}mole/L$

Therefore, the solubility of nitrogen in water at an atmospheric pressure will be, $2.5125\times 10^{-4}mole/L$

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3 years ago

1.<br> Draw the Dot Structure for Na!

stepladder [879]

Answer:

Na ·

Explanation:

Hello!

In this case, since the Lewis dot structure of any element illustrates the number of valence electrons at the outer shell; we can set up the electron configuration of sodium to obtain:

$Na^1^1\rightarrow 1s^2,2s^2,2p^6,3s^1$

We can see there is only one valence electron, for that reason the Lewis dot structure is:

Na ·

Whereas the dot represents the valence electron.

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They use many tools depending on what they want to investigate hopefully this helped!

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umka2103 [35]

Complete question from other source attached

Answer:

Explanation:

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