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densk [106]
3 years ago
6

Olaf takes a picture of his dog using a digital camera. Which is true regarding the image of the dog detected by sensors in the

camera?
a forms where light rays coming from the dog converge.
b It can only be seen from the same side of the lens as the dog.
c It forms where light rays coming from the camera spread apart.
d It can only be seen when the camera lens is very close to the dog.
Physics
2 answers:
trasher [3.6K]3 years ago
6 0

Answer: a. forms where light rays coming from the dog converge.

Explanation:

While photographing through digital camera, the light from the object through the lens converges and falls on image sensor.

The image breaks into many pixels and color and brightness of each pixel is measured and stored in form of number. This forms a digital image.

Thus, the correct option is a because the lens converges the light coming from the object onto the sensor.

SSSSS [86.1K]3 years ago
6 0

Answer:

A

Explanation:

I got A when i went back through i was right

good luck homes

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A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.
Rainbow [258]

Answer:

<em>The change of momentum of the dart is 0.84 Nw.s</em>

Explanation:

<u>Impulse and change of momentum</u>

The change in momentum of an object is its mass times the change in its velocity:

\Delta p=m\Delta v=m(v_2-v_1)

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

\Delta p=F.\Delta t

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

\Delta p=14*0.06=0.84

The change of momentum of the dart is 0.84 Nw.s

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What is the change in internal energy if 60 J of heat is released from a system and 30 J of work is done on the system? Use U =
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The change in internal energy of the system is +30 J

Explanation:

We can solve this problem by using the first law of thermodynamics, which states that the change in internal energy of a system is given by the equation:

\Delta U = Q -W

where

\Delta U is the change in internal energy

Q is the heat absorbed by the system (positive if it is absorbed, negative if it is released)

W is the work done by the system (positive if it is done by the system, negative if it is done by the surroundings on the system)

Therefore, in this problem, we have

Q=-60 J (heat released by the system)

W=-30 J (work done on the system)

Therefore, the change in internal energy is

\Delta U = -60 - (-30) = +30 J

Learn more about thermodynamics:

brainly.com/question/4759369

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