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expeople1 [14]
2 years ago
15

A Turkey is shot straight up, it takes the turkey 3.16 seconds to reach its maximum height. A) What is the velocity of the turke

y at its maximum height. B) What was its initial velocity? C) What is the greatest height it reaches? D)What is its final position exactly 5.00 seconds after it is launched? (Assuming that upwards is positive​
Physics
1 answer:
Ede4ka [16]2 years ago
6 0

Answer:

The velocity of an object thrown straight up would be zero at maximum height (just before it starts falling)

Find the initial velocity:

Time = speed/gravitational constant.

Speed = gravitational constant * time

Initial speed = 9.81*3.16

Initial speed = 30.9996

Maximum height:

h = Vinitial^2/ 2g

h = 960.9752/ 2*9.81

h = 48.979368

D)

Displacement after time = vinital * t - 0.5*g*t^2

So: 32.373

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shtirl [24]

Answer:

-30m/s

Explanation:

Given:

Initial velocity of object  = 200 feet/second

Final velocity of object  = 50 feet/second

Time of travel = 5 seconds

To calculate acceleration of the object we will find the rate of change of velocity with respect to time.

So, acceleration "a" is given by:

a=\frac{v_f-v_i}{t}

where vf represents final velocity, vi represents initial velocity and  is time of travel.

Plugging in values to evaluate acceleration.

a=\frac{50-200}{5}

a=\frac{-150}{5}

a= -30m/s

The acceleration of the object is -30m/s  

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netineya [11]

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The final velocity of the vehicle is 10.39 m/s.

Explanation:

Given;

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v² = u² + 2ah

v² = 0 + 2 x 2.7 x 20

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v = √108

v = 10.39 m/s

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