Question

A Turkey is shot straight up, it takes the turkey 3.16 seconds to reach its maximum height. A) What is the velocity of the turkey at its maximum height. B) What was its initial velocity? C) What is the greatest height it reaches? D)What is its final position exactly 5.00 seconds after it is launched? (Assuming that upwards is positive​

Answer 1

Answer:

The velocity of an object thrown straight up would be zero at maximum height (just before it starts falling)

Find the initial velocity:

Time = speed/gravitational constant.

Speed = gravitational constant * time

Initial speed = 9.81*3.16

Initial speed = 30.9996

Maximum height:

h = Vinitial^2/ 2g

h = 960.9752/ 2*9.81

h = 48.979368

D)

Displacement after time = vinital * t - 0.5*g*t^2

So: 32.373