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4 years ago

Perform the requested operation or operations. f(x) = x-5/8 g(x) = 8x + 5 find g(f(x))

2 answers:

6 0

We assume
$f(x)=\dfrac{x-5}{8}$
When this is written using plain text, parentheses are required in order to show what the numerator of the fraction is: f(x) = (x-5)/8.

g(f(x)) = g((x-5)/8)
= 8((x-5)/8) +5
= (x-5) +5
= x

g(f(x)) = x

NARA [144]4 years ago

5 0

Just to confirm is it x-5/8 or (x-5)/8

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Answer:

x = 18.5 (large) , y = 6.25 (small)

Step-by-step explanation:

Let's start by assigning variables to each type of box.

The large box we will call "x"

The small box we will call "y"

We know that 8x + 4y = 173 (kilograms)

And 3x + 2y = 68 (kilograms)

Since we set up a system of equations, we can now use elimination, by multiplying the entire bottom equation by -2, to get rid of the "y" variable.

8x + 4y = 173

3x(-2) + 2y(-2) = 68(-2)

-6x + -4y = -136 (side note: notice how the "y"'s would cancel each other out because -4y + 4y equals 0)

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2x = 37

x= 18.5

Now that we have x, just substitute it into any of the equations to get y.

You will see that y = 6.25

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3 years ago

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Step-by-step explanation:

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3 years ago

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

$H_0 : \sigma = 10$

$H_1 : \sigma \neq 10$

The test statistics can be computed as follows:

$X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}$

$X^2 = \dfrac{(36 -1)10.1^2 }{10^2}$

$X^2 = \dfrac{(35)102.01 }{100}$

$X^2 = \dfrac{3570.35 }{100}$

$X^2 =35.704$

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703 ( to four decimal places)

Decision Rule : To reject the null hypothesis if P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.

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4 years ago