#include<studio.h>
int main( )
{
int n;
int a,b,c,d,x,y;
int avarage;
printf("enter value of n:\n");
scanf("%d",&n);
printf("enter value of a:\n,b:\n,c:\n,d:\n,x:\n,y:\n);
scan f("%d\%d\n%d\n%d\n%d\n%d\n",&a,b,c,d,x,y);
sum=(a+b+c+d+x+y);
avarage=(sum/n);
print f("%d",avarage);
if
{
n=positive interger
}
else
{
printf ("n must be positive");
}
return 0;
}
Answer:
Explanation:
The problem is based on interference in thin films
refractive index of water is more than given oil so there will be phase change of π at upper and lower layer of the film .
a )
for constructive interference , the condition is
2μt = nλ where t is thickness of layer , μ is refractive index , λ is wavelength and n is order of the fringe
Putting the values
2 x 1.27 t = n x 640
2 x 1.27 t = 640 ( for minimum thickness n = 1 )
t = 252 nm .
b )
2 x 1.27 t = m₁ λ₁
for destructive interference
2μt = (2m₂+1)λ₂/2
2 x 1.27 t =(2m₂+1)λ₂/2
m₁ λ₁ = (2m₂+1)λ₂/2
2m₁λ₁ = (2m₂+1)λ₂
2m₁ / (2m₂+1) = λ₂ / λ₁
2m₁ / (2m₂+1) = 548/ 640
2m₁ / (2m₂+1) = .85625
2m₁ = .85625 (2m₂+1)
This is the required relation between m₁ and m₂
Since power = work done/time, 60= work done/120, work done = 120*60 = 7200. So,work done = 7200N (Newton).
I'm not sure if you're supposed to convert the seconds to time.
Out of the following choices, Newton's Third Law of Motion states that when one objects exerts a force on a second object, the forces are equal in magnitude and opposite in direction.
Answer:
true
Explanation:
a wheelbarrow has its load situated between the fulcrum and the force the wheel Barrow is 2nd class because of its resistance between the force and the axis