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topjm [15]
3 years ago
6

FILL IN THE BLANKS!

Physics
1 answer:
Aleksandr [31]3 years ago
8 0
1. First blank is A. Conductors
Second blank is D. Insulators

2. C. Heat
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An oil layer that is 5.0 cm thick is spread smoothly and evenly over the surface of water on a windless day. A light ray from th
marshall27 [118]

Answer:

The angle of refraction in water 32.12°.

Explanation:

Given that,

Thickness = 5.0 cm

Index of refraction for oil = 1.15

Index of refraction for water = 1.33

Angle = 45°

We need to calculate the angle of refraction

When the ray of light enters from air to oil

Using formula of refraction

n_{a}\sin\theta_{a}=n_{o}\sin\theta_{o}

Where, n_{a} = refractive index of air

n_{0} = refractive index of oil

Put the value into the formula

1\times\sin45=1.15\sin\theta_{o}

\sin\theta_{o}=\dfrac{1}{\sqrt{2}\times1.15}

\sin\theta_{o}=0.6148

\theta_{o}=sin^{-1}0.6149

\theta_{o}=37.94^{\circ}

When the ray of light enters from oil to water

Using formula of refraction

n_{0}\sin\theta_{0}=n_{w}\sin\theta_{w}

Where,  n_{w} = refractive index of water

1.15\times\sin37.94^{\circ}=1.33\sin\theta_{w}

\sin\theta_{w}=\dfrac{1.15\sin37.94^{\circ}}{1.33}

\theta_{w}=\sin^{-1}0.53163

\theta_{w}=32.12^{\circ}

Hence, The angle of refraction in water 32.12°.

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