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Illusion [34]
3 years ago
5

Newton’s Third Law of Motion states that when one object exerts a force on a second object, the forces are __________________.

Physics
1 answer:
Bezzdna [24]3 years ago
6 0
Out of the following choices, Newton's Third Law of Motion states that when one objects exerts a force on a second object, the forces are equal in magnitude and opposite in direction. 
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Suppose a shrimp has been put on the ground that has just been taken out of water.Now touch the shrimp from a distance by a stic
Alex777 [14]

Answer:

yes

Explanation:

I would say yes because it's exerting some type of force as it reacts to the stick to make it jump straight in an upwards direction

4 0
2 years ago
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Use the diagram below modeling a football kicked from a horizontal surface B
djyliett [7]
B is the correct one
5 0
2 years ago
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A high jumper jumps 2.04 m. If the jumper has a mass of 67 kg, what is his gravitational potential energy at the highest point i
Mariulka [41]

Answer: 1339.5 joules

Explanation:

Gravitational potential energy, GPE is the energy possessed by the jumper as he moves against gravity.

Thus, GPE = Mass m x Acceleration due to gravity g x Height h

Since Mass = 67kg

g = 9.8m/s^2

h = 2.04 metres

Thus, GPE = 67kg x 9.8m/s^2 x 2.04m

GPE = 1339.5 joules

Thus, the gravitational potential energy at the highest point is 1339.5 joules

3 0
3 years ago
how long would it take for a resultant upward force of 100N to increase the speed of 50kg object from 100m/s to 150m/s​
ValentinkaMS [17]

Answer:

25 sec

Explanation:

F = ma

100 = 50 a

a = 2 m/s^2

vf = vo + at

150 = 100 +  2 t

50 = 2 t

t = 25 sec

7 0
2 years ago
The mass of a spacecraft is about 435 kg . An engine designed to increase the speed of the spacecraft while in outer space provi
svlad2 [7]

Answer:

Δ v =  125 m/s

Explanation:

given,

mass of space craft = 435 Kg

thrust = 0.09 N

time = 1 week

       = 7 x 24  x 60 x 60 s

change in speed of craft = ?

Assuming no external force is exerted on the space craft

now,

T= m_s a

a=\dfrac{T}{m_s}

a =\dfrac{0.09}{435}

a = 2.068 x 10⁻⁴ m/s²

using equation of motion

Δ v = a t

Δ v = 2.068 x 10⁻⁴ x 7 x 24 x 60 x 60

Δ v =  125 m/s

3 0
3 years ago
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