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Illusion [34]
3 years ago
5

Newton’s Third Law of Motion states that when one object exerts a force on a second object, the forces are __________________.

Physics
1 answer:
Bezzdna [24]3 years ago
6 0
Out of the following choices, Newton's Third Law of Motion states that when one objects exerts a force on a second object, the forces are equal in magnitude and opposite in direction. 
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The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0
monitta
Use Coulomb law: F = k * q1*q2 / (r^2), where k = 9.00 * 10^9 N.m^2/C^2

F = 9.00 * 10^9 N.m^2/C^2 * 2.4*10^-8 C * 1.8*10^-6 C / [0.008m]^2 = 38.88 * 10^ -5 N

F = 39 * 10 -5N


4 0
3 years ago
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Jan is holding an ice cube. What causes the ice to melt?
zmey [24]
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3 years ago
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Answer:

it is a.health record documentation

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3 years ago
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mars1129 [50]
If there are no windows, then the illumination in the room depends
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4 0
3 years ago
For small amplitudes of oscillation the motion of a pendulum is simple harmonic. Consider a pendulum with a period of 0.550 s Fi
Ivenika [448]

To solve this problem we will use the concepts related to the expression of energy for harmonic oscillator. From our given values we have that the period is equivalent to

T = 0.55s

Therefore the frequency will be the inverse of the period and would be given as

f= \frac{1}{T}

f = \frac{1}{0.55}

f = 1.82s^{-1}

The ground state energy of the pendulum is,

E = \frac{1}{2} hv

E = \frac{1}{2}(6.626*10^{-34}J\cdot s)(1.82s^{-1})

E = 6.03*10^{-34}J

The ground state energy in eV,

E = 6.03 * 10^{-34}J(\frac{1eV}{1.6*10^{-19}J})

E = 3.8*10^{-15}eV

The energy difference between adjacent energy levels,

\Delta E = hv

\Delta E = (6.626*10^{-34}J\cdot s)(1.82s)

\Delta E = 12.1*10^{-34}J

4 0
3 years ago
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