a 14.24 gram rock is dropped into a graduated cylinder containing 5.7 mL of water the final volume reading on The Graduate after
1 answer:
The volume of water in the graduated cylinder is 5.7 mL, volume increases to the value 17.3 mL when a 14.24 g of rock is dropped into it.
The increase in volume is due to the added volume of rock. Thus, volume of rock can be calculated by subtracting initial volume from the final volume as follows:
On putting the values,
For correct significant figures, volume should be in 2 significant figures.
Therefore, volume of rock will be 12 mL.
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194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.
Explanation:
In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.
It is known that 1 moles of any element has 6.022×10²³ molecules.
Then 1 molecule will have moles.
So
Thus, 1.66 moles are included in BCl₃.
Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.
As it is known as 1 mole contains molecular mass of the compound.
As the molecular mass of BCl₃ will be
Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.
Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.
So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.