a 14.24 gram rock is dropped into a graduated cylinder containing 5.7 mL of water the final volume reading on The Graduate after
1 answer:
The volume of water in the graduated cylinder is 5.7 mL, volume increases to the value 17.3 mL when a 14.24 g of rock is dropped into it.
The increase in volume is due to the added volume of rock. Thus, volume of rock can be calculated by subtracting initial volume from the final volume as follows:
On putting the values,
For correct significant figures, volume should be in 2 significant figures.
Therefore, volume of rock will be 12 mL.
You might be interested in
This is a straightforward dilution calculation that can be done using the equation
where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.
Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:
Substituting in our values, we get
So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.