Answer: Volume of the tank = 0.274m^3
%V = 57.8%
Explanation: find the attached file for solution
Copper, gold and silver are three of them.
Answer:
Length = 2.453 m
Explanation:
Given:
Resistivity of the wire (ρ) = 1 × 10⁻⁶ Ω-m
Diameter of the wire (d) = 0.250 mm = 0.250 × 10⁻³ m
Resistance of the wire (R) = 50 Ω
Length of the wire (L) = ?
The area of cross section is given as:
![A=\frac{1}{4}\pi d^2\\\\A=\frac{1}{4}\times\ 3.14\times (0.250\times 10^{-3})^2\\\\A=0.785\times 6.25\times 10^{-8}\\\\A=4.906\times 10^{-8}\ m^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B4%7D%5Cpi%20d%5E2%5C%5C%5C%5CA%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%5C%203.14%5Ctimes%20%280.250%5Ctimes%2010%5E%7B-3%7D%29%5E2%5C%5C%5C%5CA%3D0.785%5Ctimes%206.25%5Ctimes%2010%5E%7B-8%7D%5C%5C%5C%5CA%3D4.906%5Ctimes%2010%5E%7B-8%7D%5C%20m%5E2)
We know that, for a constant temperature, the resistance of a wire is directly proportional to its length and inversely proportional to its area of cross section. The constant of proportionality is called the resistivity of the wire. Therefore,
![R=\rho \frac{L}{A}](https://tex.z-dn.net/?f=R%3D%5Crho%20%5Cfrac%7BL%7D%7BA%7D)
Expressing the above in terms of length 'L', we get:
![L=\frac{RA}{\rho}](https://tex.z-dn.net/?f=L%3D%5Cfrac%7BRA%7D%7B%5Crho%7D)
Plug in the given values and solve for 'L'. This gives,
![L=\frac{50\times 4.906\times 10^{-8}}{1\times 10^{-6}}\ m\\\\L=\frac{2.453}{1}=2.453\ m](https://tex.z-dn.net/?f=L%3D%5Cfrac%7B50%5Ctimes%204.906%5Ctimes%2010%5E%7B-8%7D%7D%7B1%5Ctimes%2010%5E%7B-6%7D%7D%5C%20m%5C%5C%5C%5CL%3D%5Cfrac%7B2.453%7D%7B1%7D%3D2.453%5C%20m)
Therefore, length of No. 30 wire (of diameter 0.250 mm) is 2.453 m.
A wooden stick would be best.
The wire and the wrench are both metal and therefore are able to conduct electricity.
Using your finger is obviously dangerous.
Wood is not a conductor so it is the best answer.
Nevermind that one i dont know sorry