Answer:
Part a)
x = 3.95 cm
Part b)
x = - 11.9 cm
Explanation:
Part a)
Since both charges are of same sign
so the position at which net force is zero between two charges is given as
here we know that
square root both sides
Part b)
Since both charges are of opposite sign
so the position at which net force is zero will lie on the other side of smaller charges is given as
here we know that
square root both sides
so on x axis it will be at x = - 11.9 cm
Answer:
Car C
Explanation:
The length of the deformed crumple zone is significantly longer in Car C, so the average deceleration was lower. The lower acceleration puts less stress on the dummy. Car C better protected the dummy.
By a process called osmosis
The frictional force exerted by the road on the car is 3000N
Given the mass of the car is 1000 kg , the velocity of the car is 20m/s
and the time is 6.6s
We need to find the frictional force exerted by the road on the car
We know that Force = mass * acceleration
Now here Mass is given but acceleration is not given
So, we will find acceleration by using the formula v = u+at
Where u = 0
v = 20m/s
a = ?
t = 6.6
Substitute the values in the formula We get
v = u+at
20 = 0+(a)(6.6)
20/6.6 = a
∴ a = 3.03 m/s^2
Rounding to nearest tenth is 3m/s^2
Hence the acceleration is 3m/s^2
Now substituting the value of acceleration in F = ma
Where m = mass
a = acceleration
F = 1000*3
∴ F = 3000N
Hence the frictional force exerted by the road on the car is 3000 N
Learn more about Frictional force here
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We can use the relation of ohm's law to find out the resistance of wire
given that
V = 59 volts
i = 2 A
now as per above formula
So resistance of wire is 29.5 ohm.