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rewona [7]
3 years ago
13

The rate constant for this second‑order reaction is 0.610 M − 1 ⋅ s − 1 0.610 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product

s How long, in seconds, would it take for the concentration of A A to decrease from 0.860 M 0.860 M to 0.260 M?
Chemistry
1 answer:
Darya [45]3 years ago
8 0

Answer: It takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

k = rate constant = 0.610M^{-1}s^{-1}

a_0 = initial concentration = 0.860 M

a= concentration left after time t = 0.260 M

\frac{1}{0.260}=0.860\times t+\frac{1}{0.860}

t=3.120s

Thus it takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

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Answer with Explanation:

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Carbohydrates are made up of "monosaccharides." These are simple sugars and are considered small carbohydrates. On the contrary, "polysaccharide" is an example of a large carbohydrate.<em><u> Monosaccharides are soluble in water</u></em><em> </em>while<em><u> many polysaccharides are not soluble in water.</u></em>

The high solubility of monosaccharides is mainly due to the presence of hydroxide (OH) groups. These groups are always ready to bond with water (H₂O). Many polysaccharides are not soluble in water because of <em>intermolecular interactions</em> that prevents it from binding with water. Its dissolution process is different when compared to the smaller molecules.

So, this explains the answer.

5 0
3 years ago
Which one of the following compounds is not covalent?
denpristay [2]
KCI is not a covalent compound, it is an ionic compound. 
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5 0
3 years ago
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The oxidizing agent in 2H2S + 3O2 → 2SO2 + 2H2O is
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Hello, Ginamuhs2!

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I hope this helps;)

8 0
3 years ago
Number of moles in 1.806*10^22 molecules of nitrogen
Fynjy0 [20]
Hi there!

• Avogadro's number = 6.023 × 10²³
• No.of molecules in N = 1.806 × 10²²  [ Given ]

It's known that :-

Number of molecules = Moles × Avogadro's number

=> 1.806 × 10²² = Mol. × 6.023 × 10²³

=> Mole = \dfrac {1.806 \cdot 10^{22} }{6.023 \cdot 10^{23} }

=> Moles = 0.03 mol.

Hence, 0.03 mol. is th' required answer.

~ Hope it helps!
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Inessa [10]

Answer:

I think the answer is C- radiation

Explanation:

If its not C its A Hope this helps forgive me if i'm wrong :/

8 0
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