4 years ago

I need help with #2 and #4 please

Chemistry

1 answer:

Arte-miy333 [17]4 years ago

4 0

For #4 is 298.48 hope it is correct

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Nitric oxide can be oxidized in air to form nitrogen dioxide. At normal atmospheric concentrations this is a very slow process.

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exothermic

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3 years ago

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4 years ago

Hello

nordsb [41]

Answer:

The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.

Explanation:

Let the mass of silver ornament be x.

Mass of gold polished on an ornament = 1% of x= 0.1 x

Moles of silver = $\frac{x}{108 g/mol}$

Number of atoms = $Moles\times N_A$

Where : $N_A$ = Avogadro number

Moles of gold = $\frac{0.1x}{197 g/mol}$

Silver atoms = $\frac{x}{108 g/mol}\times N_A$

Gold atoms = $\frac{0.1x}{197 g/mol}\times N_A$

The ratio of the number of atoms of gold and silver in the ornament:

$=\frac{\frac{0.1x}{197 g/mol}\times N_A}{\frac{x}{108 g/mol}\times N_A}$

= 197 : 1080

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3 years ago