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aksik [14]
3 years ago
13

I need help with #2 and #4 please

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
4 0
For #4 is 298.48 hope it is correct
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Using the following equation how many grams of water you would get from 886 g of glucose:
ankoles [38]

Answer:

531.6g

Explanation:

Total moles of glucose in this case is: 886/180= 4.922 (mole)

For every 1 mole glucose we get 6 mole water

-> Mole of water is: 4.922 * 6= 29.533 (mole)

weight of water is 18. Therefore, total weight of water that we will have from 886g of glucose are: 25.933*18= 531.6g

8 0
3 years ago
A catalyst decreases the activation energy of a particular exothermic reaction by 34 kJ/mol, to 57 kJ/mol. Assuming that the mec
vagabundo [1.1K]

Answer:

the activation energy for the uncatalyzed reverse reaction is 83kJ/mol

Explanation:

see the attached file

4 0
3 years ago
Please answer fast, shouldn't take long to do ^-^ (will give brainliest)
Anna [14]

Answer:

B

Explanation:

5 0
3 years ago
How many grams of tin would occupy 5.5 L if it had a density of 7.265
lisabon 2012 [21]
In order to find the mass of tin with the given volume of 5.5 L and density of 7.265, we will use the formula
Density = Mass / Volume

We will just multiply both sides of the equation by the volume and we will get:
Mass = Volume x Density

We can now solve the problem by substituting the given.

Mass = 5.5 L x 7.265 g/L
Mass = 39.96 g

Answer: there are 39.96 grams of tin

7 0
3 years ago
How many grams of sodium are in 0.820 moles of na2so4?
s344n2d4d5 [400]
<span>the molar mass of a compound is the sum of the products of the atomic masses by the number of atoms of the element.
molar mass of Na</span>₂SO₄<span> is - 142 g/mol.
1 mol of </span>Na₂SO₄<span> has a mass of 142 g.
In 1 mol of </span>Na₂SO₄<span> the mass of Na is 23 g/mol x 2 = 46 g.
                             
Mass of Na in 1 mol of </span>Na₂SO₄ is - 46 g
                           
mass of Na in 0.820 mol of Na₂SO₄ - 46 g /1 mol x 0.820 mol = 37.72 g.
mass of Na is 37.72 g
5 0
3 years ago
Read 2 more answers
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