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aksik [14]
3 years ago
13

I need help with #2 and #4 please

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
4 0
For #4 is 298.48 hope it is correct
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8CO + 17H2 → C8H18 + 8H2O
nekit [7.7K]

\frac{6.50mole CO}{1} \frac{17mole H2}{8mole CO}\frac{2 gram H2}{1mole H2}  =27.625

3 sig figs= 27.6

4 0
2 years ago
A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N
vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

React         0.0733α          α/2                3/2α

Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

3 0
3 years ago
What is another name for the sunlit zone of the ocean?
motikmotik

Answer:

photic zone

Explanation:

i hope it will help

4 0
3 years ago
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<span>protect it by covering it by lyophilic sol.</span>
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Oceans are the most common of course
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