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asambeis [7]
2 years ago
11

How many moles of sulfur dioxide (SO2) are required to produce 5.0 moles of sulfur (S) according to the following balanced equat

ion? SO2 + 2H2S - 3S + 2H2O​
Chemistry
2 answers:
Zepler [3.9K]2 years ago
5 0

Answer: 1.7

Explanation:

scoundrel [369]2 years ago
3 0

Answer:

1.67 moles

Explanation:

From the balanced equation of reaction:

                     SO_2 + 2H_2S -> 3S + 2H_2O

1 mole of sulfur dioxide, SO2, is required to produce 3 moles of sulfur, S.

<em>If 1 mole SO2 = 3 moles S, then, how many moles of SO2 would be required for 5 moles S?</em>

     Moles of SO2 needed = 5 x 1/3

                   = 5/3 or 1.67 moles

Hence, <u>1.67 moles of SO2 would be required to produce 5.0 moles of S.</u>

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castortr0y [4]
Molarity = moles / liter

a) M = 2/4 = 0.5 M

b) Moles = 4/(30 + 16 + 1)
= 0.085
M = 0.085 / 2 = 0.0425 M

c) Moles = 5.85 / (23 + 35.5)
= 0.1
M = 0.1 / 0.4
= 0.25 M
3 0
3 years ago
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1.3 × 1010 molecules
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4 0
3 years ago
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 C, and the temperature af
Licemer1 [7]

Answer:

fH = - 3,255.7 kJ/mol

Explanation:

Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
3 years ago
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