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asambeis [7]
2 years ago
11

How many moles of sulfur dioxide (SO2) are required to produce 5.0 moles of sulfur (S) according to the following balanced equat

ion? SO2 + 2H2S - 3S + 2H2O​
Chemistry
2 answers:
Zepler [3.9K]2 years ago
5 0

Answer: 1.7

Explanation:

scoundrel [369]2 years ago
3 0

Answer:

1.67 moles

Explanation:

From the balanced equation of reaction:

                     SO_2 + 2H_2S -> 3S + 2H_2O

1 mole of sulfur dioxide, SO2, is required to produce 3 moles of sulfur, S.

<em>If 1 mole SO2 = 3 moles S, then, how many moles of SO2 would be required for 5 moles S?</em>

     Moles of SO2 needed = 5 x 1/3

                   = 5/3 or 1.67 moles

Hence, <u>1.67 moles of SO2 would be required to produce 5.0 moles of S.</u>

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An organic compound was extracted into dichloromethane and then the aqueous layer is shaken with saturated sodium chloride solut
Ilya [14]

Answer: option A. to decrease the solubility of the organic product in water

Explanation: sodium chloride solution act as a drying agent to remove water from an organic compound that is in solution. The salt water works to pull the water from the organic layer to the water layer,therby decreasing

6 0
3 years ago
During the combustion of a peanut that weighed 0.341 g, the temperature of the 100 mL of water in the calorimeter rose from 23.4
blondinia [14]

Answer:

119 kCal per serving.

Explanation:

The heat energy necessary to elevates water's temperature from 23.4°C to 37.9°C can be calculated by the equation below:

Q = mcΔT

Q: heat energy

m: mass in g

c: specific heat capacity in cal/g°C

ΔT = temperature variation in °C

m is the mass of water, considering the density of water to be 1g/mL, 100 mL of water weights  100g. Therefore:

Q = 100 g x 1.00 cal/g°C x (37.9 - 23.4)°C

Q = 1450 cal

1450 cal ____ 0.341 g peanuts

x             ____  28 g peanuts

x = 119061.58 cal

This means that the cal from fat per serving of peanuts is at least 119 kCal.

3 0
3 years ago
How many mol of phosphorus are obtained if 74.85 mol of carbon is used​
mixer [17]

Answer:

34.73

Explanation:

6 0
3 years ago
What is the pH of a 0.050 M triethylamine, (C2H5)3N, solution? Kb for triethylamine is 5.3 ´ 10-4. Question options: 1) 11.69 2)
blsea [12.9K]
<span>the pH of a 0.050 M triethylamine, is 11.70
</span>
For triehtylamine, (C_{2}H_{5})_{3}N, the reaction will be
(C_{2}H_{5})_{3}N + H_{2}O ---\ \textgreater \ ( C_{2}H_{5})_{3}NH^{+} + OH^{-}

 and we know, pH = -log[H+] and pOH = -log[OH-]

Also, pOH + pH = 14

Now, the Kb value  = 5.3 x 10^-4

And kb =  \frac{( [( C_{2}H_{5})_{3}NH^{+} ]*  OH^{-} )}{[( C_{2}H_{5})_{3}N]}

 thus, [OH-] =(5.3 ^ 10-4) ^2 / 0.050

                    =0.00516 M 

Thus, pOH = 2.30 
 pH = 14 - pOH = 11.7
6 0
3 years ago
Balance the equation 2kclo3 3o2 + kcl
sergij07 [2.7K]
Answer is 2KClO3 3O2 + 2KCl
5 0
3 years ago
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