For this simulation, there are 5 numbers that we can draw. One of the numbers will result in seeing the groundhog. (1/5 or 0.20) To find the probability that Jay will see the groundhog 4 years in a row, we would use the following equation: 1/5•1/5•1/5•1/5
We would multiply the odds of getting a certain outcome by the number of time we want that outcome.
The odds that Jay will see the groundhog for the next for years is 0.0016, or .16%.
You just multiply 6 times 3/4, .75, or 75%.
6 times .75 = 4.50 yards
The factor of <span>15xy − 45x − 6y + 18 is 3(y-3)(5x-2).</span>
Find factors of 12 and 21
Divide 3 from both numerator and denominator.
(12/21)/(3/3) = 4/7
4/7 is your ratio equivalent to 12/21
hope this helps
-2, -1, 0
These would be the options
