All categories

3 years ago

Janette has 6 puppies. she gives away 3. how many does she have left?

Mathematics

1 answer:

kvasek [131]3 years ago

4 0

Um 3 unless she gave them away to her brother then she still would have 6

You might be interested in

Six more than 1/5 a number is 12. What is the number

suter [353]

Answer:

Step-by-step explanation:

let x be the number

6+1/5x=12

1/5x=12-6

1/5x=6

x=5*6

x=30

check: 6+(1/5*30)=6+6=12

8 0

2 years ago

Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit

andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: $d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ . We can plug in $4\sqrt{2}$ = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

$4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\$

$(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2$

$32 = (4)^2 + (7-k)^2$

$32 = 16 + (7-k)^2$

$32 - 16 = (7-k)^2$

$16 = (7-k)^2$

$\sqrt{16} = (7-k)$

$4 = 7-k$

$k = 3$

4 0

2 years ago

R(x)=x^3+5x^2-2x-24 Plot the zero(s) of the function.

nevsk [136]

:) Brainliest pls?

Answer:

The zeros are {2, -3, -4} which need to be plotted on the x-axis.

Step-by-step explanation:

I'll find the zeros, aka x-intercepts, and you could probably graph them.

To find the zeros, let's factor this polynomial:

r(x) = (x - 2)(x^2+7x+12)

r(x) = (x - 2)(x + 3)(x + 4)

The zeros are {2, -3, -4} which need to be plotted on the x-axis.

6 0

2 years ago

Writer and solve a real-word promblem involving the multiplication of a fraction and a whole number whose is between 10and15

pickupchik [31]

Give me an operation like the one you are talki ng about and I can solve it

8 0

2 years ago

Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end

IRISSAK [1]

Answer:

x = 0.667 and y = -0.6

Step-by-step explanation:

Given that,

6x + 5y = 1 ....(1)

6x - 5y = 7 ...(2)

We need to solve the above equations.

Subtract equations (1) and (2)

6x + 5y -(6x - 5y) = 1-7

6x+5y-6x+5y = -6

10y=-6

y = -0.6

Put the value of y in equation (1).

6x + 5(-0.6) = 1

6x = 1-5(-0.6)

6x = 4

x = 0.667

Hence, first step is to subtract equation (1) and (2) then put the value of y in equation (1).

3 0

2 years ago