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2 years ago

6.3. A __________ is used to indicate the base material that needs to be beveled.

Engineering

1 answer:

Ivan2 years ago

4 0

Answer:

A <u>break in the arrow</u> is used to indicate the base material that needs to be beveled

A. Break in the arrow

Explanation:

In a weld that involves the welding of a joint that has a, a bevel, flare bevel, or J-groove, the side that requires beveling (chamfering) preparation in the welded joint before welding is indicated by an arrow having a definitive before pointing to the beveled member

However, the break in the arrow could excluded when the side to be chamfered is unmistakable

Therefore, the break in the arrow is the option that is used to indicate which of the material that is to be beveled.

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Code

#include<stdio.h>

#include<stdlib.h>

#include<string.h>

#define size 200

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3 years ago

Find the differential and evaluate for the given x and dx: y=sin2xx,x=π,dx=0.25

Sedaia [141]

By applying the concepts of differential and derivative, the differential for y = (1/x) · sin 2x and evaluated at x = π and dx = 0.25 is equal to 1/2π.

<h3>How to determine the differential of a one-variable function</h3>

Differentials represent the <em>instantaneous</em> change of a variable. As the given function has only one variable, the differential can be found by using <em>ordinary</em> derivatives. It follows:

dy = y'(x) · dx (1)

If we know that y = (1/x) · sin 2x, x = π and dx = 0.25, then the differential to be evaluated is:

$y' = -\frac{1}{x^{2}}\cdot \sin 2x + \frac{2}{x}\cdot \cos 2x$

$y' = \frac{2\cdot x \cdot \cos 2x - \sin 2x}{x^{2}}$

$dy = \left(\frac{2\cdot x \cdot \cos 2x - \sin 2x}{x^{2}} \right)\cdot dx$

$dy = \left(\frac{2\pi \cdot \cos 2\pi -\sin 2\pi}{\pi^{2}} \right)\cdot (0.25)$

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By applying the concepts of differential and derivative, the differential for y = (1/x) · sin 2x and evaluated at x = π and dx = 0.25 is equal to 1/2π.

To learn more on differentials: brainly.com/question/24062595

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2 years ago