A wax is a type of lipid. Waxes are nonpolar, so they are not soluble in water.
Hello there.
<span>Now we add 0.15 mol of naoh to 1.00 liter of the solution that was given in part 1. what is the ph of the solution after the naoh addition? answer in units of ph.
</span><span>not sodium nitrate</span>
Answer:
The pH of the solution could 10
Explanation:
hope it helps you
Answer:
0.4515 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 10.0 mL
M₂ = 0.100 M
V₂ = 45.15 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 10.0mL = 0.100 M * 45.15 mL
M₁ = 0.4515 M
Hence, the concentration of the acetic acid = 0.4515 M
Answer: 19.08 cm^3
Explanation:
Density = mass/vol (Rearrange to solve for vol)
Vol = mass/density
Vol = 150/7.86 = 19.08 cm^3
