Answer:
V₂ = 45.53 L
Explanation:
Given data:
Initial temperature = 850 K
Initial volume = 65 L
Initial pressure = 450 KPa
Final temperature = 430 K
Final pressure = 325 KPa
Final volume = ?
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa
V₂ = 12577500 KPa .L. K / 276250 K. KPa
V₂ = 45.53 L
It is a completely true statement that a <span>base increases the OH- ion concentration of water. The correct option among the two options that are given in the question is the first option. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>
<span>The water soaks in the cracks of rocks, freezes and expands breaking the rock apart.</span>
The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,
PE=mgh
PE=(6 kg)(9.8 m/s^2)(1 m)
PE=58.8 kg•m^2/s^2 or 58.8 Newtons
The GPE of the bowling ball under these conditions would be about 59 Newtons.
Hope this helps!
Answer:
2,14 g / ml
Explanation:
Sabemos que el volumen de una sustancia es igual al cambio de volumen del agua cuando el objeto en cuestión se sumerge en el agua.
Dado que el volumen original del agua = 50 ml
Volumen de agua después de sumergir el objeto = 120 ml
Masa del objeto = 150 g
Ahora,
Densidad = masa / volumen
Densidad = 150g / 120-50 ml
Densidad = 150/70 ml
Densidad = 2,14 g / ml
