Ok what you want. I got u
C = n/V
n = C×V
n = 4,41M × 1,25L
n = 5,5125 mol
mKI: 39+127 = 166 g/mol
1 mol --------- 166g
5,5125 mol --- X
X = 166×5,5125 = 915,075g KI
:)
The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.
<h3>How do we calculate molar mass?</h3>
Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.
Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:
Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)
Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.
To know more about molar mass, visit the below link:
brainly.com/question/18983376
#SPJ1
Answer:
you have to give us the product in order for us to know the limiting reactant.
<span>Answer:
Once these values are put into the equation delta Q=mc delta T it will give you the same value for Q (change in energy) if the same fuel is used
50mL will mean it gets heated quicker making the experiment quicker
200mL would take longer to heat for the same change in temperature causing a longer experiment.</span>
