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NARA [144]
4 years ago
9

Algebra 2 help!! Find the value of k

Mathematics
1 answer:
Oksana_A [137]4 years ago
4 0

13  By the factor theorem, if the function is divisible by x - 3 then f(3) = 0. So we have:-

2(3)^3 + k(3)^2 + 7(3) - 3 = 0

9k = 3 - 21 - 54 = -72

k =  -72/9 =  -8 answer

14.   Similarly ,   f(-4) = 0 , so we have:-

(-4)^3 + 9(-4)^2 + k(-4) - 12 = 0

-64 + 144 - 4k - 12 = 0

4k = -64 + 144 - 12 = 68

k = 68/4

k = 17   answer

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<h3>Answer:</h3>

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<h3>Step-by-step explanation:</h3>

<em>Try the answers</em>

You can try the answers to see what works. You can expect all of the choices to match the first two terms, so try some farther down. Let's see if we can get -25 from -7.

a) 3*(-7) -4 = -21 -4 = -25 . . . . this one works

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c) -3(-7) +2 = 21 +2 = 23 . . . . ≠ -25

d) -2(-7) +1 = 14 +1 = 15 . . . . ≠ -25

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_____

<em>Derive it</em>

All these formulas depend on the previous term only, so we can write equations that show the required relationships. Let the unknown coefficients in our recursion formula be p and q, as in ...

a_n=p\cdot a_{n-1}+q

Then, to get the second term from the first, we have

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Subtracting the second equation from the first gives ...

... 2p = 6

... p = 3 . . . . . . . this is sufficient to identify the first answer as correct

We can find q from the first equation.

... q = -1 -p = -1 -3 = -4

So, our recursion relation is ...

a_n=3a_{n-1}-4

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