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3 years ago

Algebra 2 help!! Find the value of k

Mathematics

1 answer:

Oksana_A [137]3 years ago

4 0

13 By the factor theorem, if the function is divisible by x - 3 then f(3) = 0. So we have:-

2(3)^3 + k(3)^2 + 7(3) - 3 = 0

9k = 3 - 21 - 54 = -72

k = -72/9 = -8 answer

14. Similarly , f(-4) = 0 , so we have:-

(-4)^3 + 9(-4)^2 + k(-4) - 12 = 0

-64 + 144 - 4k - 12 = 0

4k = -64 + 144 - 12 = 68

k = 68/4

k = 17 answer

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What are the factors of 36x^8-49

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Answer:

Bsdjfjfdffg

Step-by-step explanation:

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3 years ago

“I think of a number, multiply it by 2, subtract 3 and multiply the result by 4."

Scorpion4ik [409]

Answer:

33x2=66

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Is this a question for a test cause if it is i'm gonna feel embarrassed

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2 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

3 years ago

Find Mean, Median, mode and range. Round to the nearest tenth.

stiv31 [10]

Answer:

Mean = 26.24

Median = 27

Mode = 32

Range = 38

Step-by-step explanation:

Plotting the original data from leaf plot

$9,11,12,12,14,17,25,25,27,32,32,32,33,35,41,42,47$

Finding Mean:

The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

$\mu=\frac{446}{17}$

= 26.24

Therefore, the range = 26.24.

Finding Median:

The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.

Ordering the data from least to greatest, we get:

9 11 12 12 14 17 25 25 27 32 32 32 33 35 41 42 47

So, the median is 27 .

Finding Mode:

The mode of a set of data is the value in the set that occurs most often.

Ordering the data from least to greatest, we get:

9 11 12 12 14 17 25 25 27 32 32 32 33 35 41 42 47

We see that the mode is 32.

Finding Range:

The range is the difference between the highest and lowest values in the data set.

Ordering the data from least to greatest, we get:

9 11 12 12 14 17 25 25 27 32 32 32 33 35 41 42 47

The lowest value is 9.

The highest value is 47.

The range = 47 - 9 = 38

4 0

3 years ago

(English to algebra) twice K results in three times the sum of k plus one

babymother [125]

i believe its 2k= 3(k+1)

8 0

3 years ago