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3 years ago

What is the value of this expression (-4)^4

Mathematics

2 answers:

tamaranim1 [39]3 years ago

8 0

Answer:

the answer is (-256)

Step-by-step explanation:

4 to the 4 is just -4 times itself four times.

-4 times itself four times broken down is:

-4 times -4 = 16

and then

16 times -4 is -64

-64 times -4 again is

-256

Hoped this helped!

lyudmila [28]3 years ago

6 0

Answer:

256

Step-by-step explanation:

and if u need in simpliest form just ask me

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If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &8
\end{cases}$

$\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8
\\\\\\
\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r
\\\\\\
0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086
\\\\\\
r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}$

6 0

3 years ago

PLEASE HELP:))))))) 15points

Zielflug [23.3K]

Answer:7 cm

Step-by-step explanation: you know everything except the radius. Use this equation to help you: 44=2*pi*radius

Divide 44 by 2pi. Then u have your radius which is 7

7 0

3 years ago

20 points if you can answer this expression and give me 2 equivalent expressions SHOW YOUR WORK PLEASE!!! 32(10j + 17 + 5j)

Roman55 [17]

Answer:

Brainliest!

Step-by-step explanation:

32(10j + 17 + 5j)

equvilatnt equations include:

320j + 32(17+5j)

32(10j+17)+160j

4 0

3 years ago

How much of a radioactive kind of thorium will be left after 14,680 years if you start with

babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

$N(t)= N_{0}e^{-kt}$

N(t) = amount after the time t

$N_{0}$ = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

$N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t}$ or more simply $N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }$