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tatiyna
3 years ago
14

, determine the approximate volume of the block.

Chemistry
2 answers:
Jobisdone [24]3 years ago
8 0
I believe the answer is A. 40 mL
olchik [2.2K]3 years ago
4 0
It c 100mL I know this it easy
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A cylinder with a moving piston expands from an initial volume of 0.350 L against an external pressure of 1.90 atm. The expansio
myrzilka [38]

Answer:

1.84 L

Explanation:

Using the equation for reversible work:

W = -P*(V_{2} - V_{1})

Where:

W is the work done (J) = -287 J.

Since the gas did work, therefore W is negative.

P is the pressure in atm = 1.90 atm.

However, work done is in joules and pressure is in atm. We can use the values of universal gas constant as a convenient conversion unit. R = 8.314 J/(mol*K);  R = 0.0821 (L*atm)/(mol*K)

Therefore, the conversion unit is 0.0821/8.314 = 0.00987 (L*atm)/J

V_{1} is the initial volume = 0.350 L

V_{2} is the final volume = ?

Thus:

(-287 J)*0.00987 (L*atm)/J = -1.9 atm*(V_{2} - 0.350) L

V_{2} = [(287*0.00987)+(1.9*0.350)]/1.9 = (2.833+0.665)/1.9 =1.84 L

7 0
3 years ago
The figure above shows the basic concepts of cell division
Cerrena [4.2K]
A. DNA is copied. 
- The cell duplicates its DNA in order to have a complete set in eac cell when it divides.

6 0
3 years ago
What will determine the number of moles in a sample
julsineya [31]

Answer:

weigh it and divide the weight by the molecular weight. :) good luck!!

Explanation:

3 0
3 years ago
Read 2 more answers
Form a hypothesis: how do you think photosynthesis is related to cellular respiration
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Answer: Photosynthesis and cellular respiration are related because the reactants for photosynthesis is the products (plus ATP) is cellular respiration. Also the products for cellular respiration is the reactants for cellular respiration.

Explanation:

5 0
3 years ago
How many grams of carbon are present in 45.0 g of CCl4?
lisabon 2012 [21]
To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:

45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present

Hope this answers the question. Have a nice day.
5 0
3 years ago
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