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JulsSmile [24]
2 years ago
7

What the equipment of diffusion?​

Chemistry
1 answer:
I am Lyosha [343]2 years ago
5 0

Answer:

liquid

a semi permeable membrane

oxygen

Explanation:

plz give me brainiest

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I’m making a transition from stare n=1 to state n=2 the hydrogen atom must
MatroZZZ [7]

Answer:

Water, 35 liters. Carbon, 20 kilograms. Ammonia, 4 liters. Lime, 1.5 kilograms. Phosphorous, 800 grams. Salt, 250 grams. Saltpeter, 100 grams. Sulfur, 80 grams. Fluorine, seven-point-five. Iron, five. Silicon, three grams. And trace

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the ingredients of the average adult,right down to the last specks of protein in your eyelashes. And even though science has given us the entire physical breakdown, there's never been a successful attempt at bringing a human to life. There's still something missing. Something scientists haven't been able to find in centuries of research. ...and in case you're wondering, all those ingredients can be bought on a child's allowance. humans can be made rather cheap. There's no magic to it.

6 0
3 years ago
According to rounding rules for addition the sum of 27.1, 34.538, and 37.68 is
Katena32 [7]
The answer should be...99.318!
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2 years ago
When reacting 45g of magnesium with oxygen, 50.0g of magnesium oxide is produced. Calculate the theoretical yield and percent yi
Veseljchak [2.6K]
Hope you are able to get it :)

5 0
3 years ago
When potassium metal is added to water, a violent reaction occurs that releases a tremendous amount of light and thermal energy.
Thepotemich [5.8K]

Answer:

An Exothermic reaction.

Explanation:

An exothermic reaction produces heat, while endothermic reactions absorb heat

5 0
2 years ago
A concentrated salt solution has a mass of 5.29 g for a 5.00 mL sample. What is the specific gravity of this solution
TiliK225 [7]

Answer:

\rho_s=1.07g/cc^3

Explanation:

From the question we are told that:

Mass M=5.29g

Volume V=5.00mL=>5.0cc^3

Generally the equation for Specific Gravity momentum is mathematically given by

Specific\ Gravity\ g= Density\ of\ Salt\ Solution\ \rho_s / Density\ of\ Water\ \rho_w

 g=\frac{ \rho_s} { \rho_w}

 \rho_s=\frac{ g} { \rho_w}

 \rho_s=\frac{ 5.29} { 5}

 \rho_s=1.07g/cc^3

7 0
3 years ago
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