we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
#SPJ1
First one is 75/100 = x/80 with 60 free throws, second best is 70/100 = x/80 with 56 free throws, and last is 65/100 = x/80 with 52 free throws
Answer:
x=-2
Step-by-step explanation:
-6/18=x/6
simplify the -6/18 into -1/3,
-1/3=x/6
cross product,
3*x=-1*6
3x=-6
x=-6/3
x=-2
Answer:
Step-by-step explanation:
Th correct one is the third box
plz mark me brainliest
Answer:
n+7
Step-by-step explanation:
Sum means add, so it's just n added to 7:
n+7 :)
