Solution for this problem is we will be using the following
formula:
Work done by applied force) = Force (applied) x s x cos θ
Where:
Force applied = 12 N
s = 13 m long
Angle = 17
So plugging in the values:
=>W (a) = 12 x 13 x cos 17
= 12 x 12.43196182
= 149.1835 J
5 m/s
30 divided by 6 is 5
Work done by the force = Force x displacement. Power = work done/time = F.s/t = F.u.t/t = F.u = 95 x 20 = 1900J. {S=ut because acceleration is zero since car is moving at constant velocity}.
The measure of the quantity of matter would be mass. Mass is measured in kilograms. I hope this helped!:)
Answer:
The actual angle is 30°
Explanation:
<h2>Equation of projectile:</h2><h2>y axis:</h2>

the velocity is Zero when the projectile reach in the maximum altitude:

When the time is vo/g the projectile are in the middle of the range.
<h2>x axis:</h2>

R=Range


**sin(2A)=2sin(A)cos(A)
<h2>The maximum range occurs when A=45°
(because sin(90°)=1)</h2><h2>The actual range R'=(2/√3)R:</h2>
Let B the actual angle of projectile

2B=60°
B=30°