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Kazeer [188]
3 years ago
7

An automobile traveling on a straight, level road has an initial speed v when the brakes are applied. In coming to rest with a c

onstant acceleration, it travels a distance x. How far would the automobile travel in coming to rest if it had the same acceleration but an initial speed 2v ?
Physics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

4x

Explanation:

Use v^{2} = u^{2} +2as to do the question.

For first instance,

0 = v^{2} +2ax -------------------( 1 )

for second instance,

0 = (2v)^{2} +2as-----------------( 2 )

So by (1) and (2),

s = 4x

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The zone of earthquakes and volcanoes surrounding the pacific ocean is called
gulaghasi [49]

Answer:

The Ring of Fire

Explanation:

The ring of fire is also called the Circum-Pacific Belt, it is a path along the pacific ocean consisting of active volcanoes and frequent earthquakes.

It has a length of approximately 40,000 kilometers. It lies on the edge of tectonic plates where the in-earth vibrations and geothermal energies are prone to erupt out.

Ring of fire inhibits about 75% o the earth's volcanoes and 95% of earthquakes occur in this region.

3 0
3 years ago
Star X has an apparent magnitude of 1. Star Y has an apparent magnitude of 4. Both stars are in the same star cluster. Which sta
sashaice [31]

Answer:

Explanation:

From the given information:

Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:

m_1 - m_2 = -2.5 log _{10} (\dfrac{L_1}{L_2})

Given that;

m_1 = 1 and

m_2 = 4

Therefore,

1 - 4 = -2.5 log _{10} ( \dfrac{L_1}{L_2})

3 = -2.5 log _{10} ( \dfrac{L_1}{L_2})

Making \dfrac{L_1}{L_2} the subject of the formula:

\implies \dfrac{L_1}{L_2}= 10^{(\dfrac{3}{2.5})}

=15.84

≅ 16

Hence, we can conclude that star X is more luminous by a factor of 16

7 0
2 years ago
A battery establishes a voltageV on a parallel-plate capacitor. After the battery is disconnected, the capacitor doesn't loss ch
Digiron [165]

Answer:

E

Explanation:

I me and my friends did a project on this

7 0
2 years ago
An electric field exerts a force of 3.00 E -4 N on a positive test charge of 7.20 E-4 C. The magnitude of the field at this loca
Step2247 [10]
3.00 E-4 / 7.20 E-4 = 0.417
answer is b
3 0
3 years ago
Read 2 more answers
How much time would it take for an object to fall 4.7 meters
alukav5142 [94]

Answer:

t = 0.97 s

Explanation:

Given that,

height, h = 4.7 m

We need to find the time taken by the object to fall 4.7 m.

Let it is t. Using second equation of kinematics to solve it such that,

h=ut+\dfrac{1}{2}gt^2

u is initial velocity, u = 0

So,

h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}}\\\\t=\sqrt{\dfrac{2\times 4.7}{9.8}}\\\\t=0.97\ s

So, the required time is equal to 0.97 seconds.

4 0
3 years ago
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