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marshall27 [118]
3 years ago
11

A bag of sugar weighs 2 kg on earth. What should it weigh in newtons on the moon, where the free-fall acceleration is 1/6 that o

n earth? Repeat for Jupiter, where g is 2.64 times that on Earth. Find the mass of the bag of sugar in kilograms at each of the three locations.
Physics
1 answer:
Elis [28]3 years ago
5 0
<span> Weight = mass x acceleration
Earths acceleration is 9.8 m/s*2
1 kg = 2.2 lbs, so 2.0 lbs x 1 kg/2.2 lbs = 0.91 kg
The bag would have a weight of 9.8 x 0.91 = 8.9 N

1. 8.9 x 1/6 = 1.5 N

2. 8.9 x 2.64 = 23.5 N

The mass of the bag at all three locations is 0.91 kg. Mass does not change, the different locations only change its weight. </span>
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HELP ASAP!!!! WILL GIVE BRAINLIEST!
Pani-rosa [81]

Answer:

Vacculoes, vesicles

Explanation:

Organelles and other structures within the cells have vesicles collectively referred to as the endo-membrane system. The Lysosomes pack up the substances, and the vesicles go through the porsous membrame and secrete the substances.

6 0
3 years ago
A 460 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exert
ollegr [7]

Answer:

The rocket should be launched at a horizontal distance of <u>6.45 m</u> left of the loop.

Explanation:

Given:

Mass of the rocket model (m) = 460 g = 0.460 kg [1 g = 0.001 kg]

Speed of the cart (v) = 3.0 m/s

Thrust force by the rocket engine (F) = 8.5 N

Vertical height of the loop (y) = 20 m

Let the horizontal distance left to the loop for launch be 'x'. Also, let 't' be the time taken by the rocket to reach the loop.

Now, there are two types of motion associated with the rocket- one is horizontal and the other vertical.

So, we will apply kinematics of motion in the two directions separately.

Vertical motion:

Given:

Force acting in the vertical direction is given as:

F_y=F-mg=8.5-0.46\times 9.8=3.992\ N

So, acceleration in the vertical direction is given as:

Acceleration = Force ÷ mass

a_y=\frac{F_y}{m}=\frac{3.992\ N}{0.46\ kg}=8.678\ m/s^2

Vertical displacement of rocket is same as the height of loop. So, y=20\ m

There is no initial velocity in the vertical direction. So, u_y=0\ m/s

Now, applying equation of motion in vertical direction. we have:

y=u_yt+\frac{1}{2}a_yt^2\\\\20=0+\frac{1}{2}\times 8.678t^2\\\\20=4.339t^2\\\\t^2=\frac{20}{4.339}\\\\t=\sqrt{\frac{20}{4.339}}=2.15\ s

Now, time taken to reach the loop is 2.15 s.

Horizontal motion:

There is no acceleration in the horizontal motion. So, displacement in the horizontal direction is equal to the product of horizontal speed and time.

Also, displacement of the rocket in the horizontal direction is nothing but the horizontal distance of its launch left of the loop. So,

x=vt\\\\x=3.0\ m/s\times 2.15\ s\\\\x=6.45\ m

Therefore, the rocket should be launched at a horizontal distance of 6.45 m left of the loop.

5 0
3 years ago
Can some one please answers number 4
Maru [420]
I think it is the core and outer core. 
hope this helped. 
5 0
3 years ago
Two cubes, one silver and one iron, have the same mass and temperature. A quantity Q of heat is removed from each cube. Which on
scoundrel [369]

Answer:

C) specific heat capacity

Explanation:

As we know that heat given to the system to change the temperature is given as

Q = ms \Delta T

here we know that

Q = thermal energy given to the system

s = specific heat capacity of the system

\Delta T = change in temperature

so here we know that

\Delta T = \frac{Q}{ms}

here we know that heat given to the two cubes is of same amount as well as the mass is same but the final temperature is different because of the specific heat capacity (s)

So correct answer would be

C) specific heat capacity

8 0
3 years ago
which element are you most likely to find as a free element rather than a compound lead or calcium, explain?
TEA [102]
Pb, if compared to Ca it is less reactive and it is a transition metal, and is highly stable alone.
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