A bag of sugar weighs 2 kg on earth. What should it weigh in newtons on the moon, where the free-fall acceleration is 1/6 that o
1 answer:
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Answer:
The magnitude of the tangential velocity is
The magnitude of the resultant acceleration at that point is
Explanation:
From the question we are told that
The mass of the uniform disk is
The radius of the uniform disk is
The force applied on the disk is
Generally the angular speed i mathematically represented as
Where is the angular displacement given from the question as
is the angular acceleration which is mathematically represented as
The moment of inertial is mathematically represented as
Substituting values
Considering the equation for angular acceleration
Substituting values
Considering the equation for angular velocity
Substituting values
The tangential velocity of a given point on the rim is mathematically represented as
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The radial acceleration at hat point is mathematically represented as
The tangential acceleration at that point is mathematically represented as
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The magnitude of resultant acceleration at that point is
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Answer:
The angle of incidence when the reflected ray is perpendicular to the incident ray = 45°
Explanation:
According to Snell's Law,
n₁ sin θ₁ = n₂ sin θ₂
When the angle between the incident ray and reflected ray is 90°, the angle of incidence is θ₁ and the angle of reflection, θ₂ = 90° - θ₁ and the index of refraction in the Snell's Law for both media would be the same, n₁ = n₂ = n
n sin θ₁ = n sin (90° - θ₁)
Note that from trigonometric relations,
Sin (90° - θ₁) = cos θ₁
n sin θ₁ = n cos θ₁
(sin θ₁)/(cos θ₁) = 1
tan θ₁ = 1
θ₁ = arctan 1 = 45°
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