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marshall27 [118]
3 years ago
11

A bag of sugar weighs 2 kg on earth. What should it weigh in newtons on the moon, where the free-fall acceleration is 1/6 that o

n earth? Repeat for Jupiter, where g is 2.64 times that on Earth. Find the mass of the bag of sugar in kilograms at each of the three locations.
Physics
1 answer:
Elis [28]3 years ago
5 0
<span> Weight = mass x acceleration
Earths acceleration is 9.8 m/s*2
1 kg = 2.2 lbs, so 2.0 lbs x 1 kg/2.2 lbs = 0.91 kg
The bag would have a weight of 9.8 x 0.91 = 8.9 N

1. 8.9 x 1/6 = 1.5 N

2. 8.9 x 2.64 = 23.5 N

The mass of the bag at all three locations is 0.91 kg. Mass does not change, the different locations only change its weight. </span>
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A basketball rolls without slipping (starting from rest) down a ramp. If the ramp is sloped by an angle of 4 degrees above the h
slavikrds [6]

Answer:

11.7 m/s

Explanation:

To find its speed, we first find the acceleration of the center of mass of a rolling object is given by

a = gsinθ/(1 + I/MR²) where θ = angle of slope = 4, I = moment of inertia of basketball = 2/3MR²

a = 9.8 m/s²sin4(1 + 2/3MR²/MR²)

  = 9.8 m/s²sin4(1 + 2/3)

  = 9.8 m/s²sin4 × (5/3)

  = 1.14 m/s²

To find its speed v after rolling for 60 m, we use

v² = u² + 2as where u = initial speed = 0 (since it starts from rest), s = 60 m

v = √(u² + 2as) = √(0² + 2 × 1.14 m/s × 60 m) = √136.8 = 11.7 m/s

4 0
3 years ago
If the torque required to loosen the nut that is holding a flat tire in a place on a car has a magnitude of 35 N•m what minimum
VashaNatasha [74]

Answer: F = 130 N

Explanation: Solution:

Convert first 27 cm to m.

27 cm  x 0.01 m / 1 cm = 0.27 m

Calculate the torque using T = Fd

Derive to find force F

F = T /d

  = 35 N.m / 0.27 m

  = 130 N

4 0
3 years ago
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A person standing at the top of mountain aconcagua would be approximately 4.3 mi high. the radius of earth is 3959 mi. what is t
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Besides ambitious, it would be 184.6 mi
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3 years ago
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How do we use information from earths climate change data in order to engineer soulutions that reduce carbon emissions and impac
masya89 [10]

Answer:

That is a very broad question. One thing that does not seem to be considered is the depletion of the ozone layer at high altitudes.

In the 1960's chlorofluorcarbons (CFC,s) became popular as refrigerants, spray can propellants, etc.  In January 1989 the Montreal Protocol was passed which has greatly reduced the use of these substances. However, it may be several decades before the ozone layer can be replaced and again absorb harmful ulraviolet rays that may be partly responsible for the increase in global warming.  

(One chlorine atom at high altitudes can be responsible for the destruction of 100,000 molecules of ozone - catalytic reaction)

7 0
2 years ago
In a long straight wire, what current is required to exert a 1.0μN force on a 1.0μC charge moving at 1.5×106m/s parallel to the
Bas_tet [7]

Answer:

Current in the wire is given as

i = 1.17 \times 10^{-7} A

Explanation:

magnetic field due to long current carrying wire is given as

B = \frac{\mu_0 i}{2\pi r}

so we have magnetic force on moving charge is given as

F = qvB

so we have

F = (1\times 10^{-6})(1.5 \times 10^6)(\frac{\mu_0 i}{2\pi (0.35)})

so we have

1\times 10^{-6} = 1.5 \times \frac{2 i}{0.35}

i = 1.17 \times 10^{-7} A

6 0
3 years ago
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