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Evgesh-ka [11]
3 years ago
5

In a transpiration experiment, the air bubble has an initial volume of 4.33 mL, and an initial pressure of 101.9 kPa. What will

be the pressure reading after the plant transpires 0.26 mL of water from the tubing

Physics
1 answer:
ira [324]3 years ago
8 0

Answer:

Explanation:is in the picture below

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I need help on 6, 7, 8, and 9
Ivahew [28]
6 is b. part B on 6 is a. 7 is a. partB ON 7 b
5 0
3 years ago
"Which of the following statements about electrons is not true?
gogolik [260]

Answer:

B) Within an atom, an electron can have only particular energies.

Explanation:

As we know that electrons have energy but apart from electrons we know that protons and neutrons inside the nucleus of atom will also have energy in them.

rest all the statements are true as we have

A) Electrons orbit the nucleus rather like planets orbiting the Sun.

TRUE, because electrons can move in stationary orbit around the nucleus

C) Electrons can jump between energy levels in an atom only if they receive or give up an amount of energy equal to the difference in energy between the energy levels.

Difference amount of energy is lost or absorbed by the electron in form of photons

D) An electron has a negative electrical charge.

Charge of an electron is given as -1.6 \times 10^{-19} C

E) Electrons have very little mass compared to protons or neutrons

Mass of an electron is given as

m_e = 9.11 \times 10^{-31} kg

mass of proton or neutron

m_p = 1.67 \times 10^{-27} kg

7 0
3 years ago
What happens at night- describing air circulation
mash [69]

Answer:

The environment is warmed by the light throughout the day, such that the temperature increases. The weather is decreasing and the temperature decreases in the night as the sun falls. There was a misunderstanding. Thanks to the density, the atmosphere becomes densest on the earth. The air becomes colder and colder when you move up.

Explanation:

Answer is above

<em><u>Hope this helps.</u></em>

5 0
3 years ago
A disk-shaped grindstone of mass 3.0 kg and radius 8.0 cm is spinning at 600 rev/min. After the power is shut off, a man continu
kolbaska11 [484]

Answer:

τ=0.060 N.m

Explanation:

By kinematics:

\omega f = \omega o-\alpha*t

Solving for α:

\alpha=\frac{\omega o-\omega f}{t}

where ωo = 600*2*π/60;   ωf = 0;    t=10s

\alpha=6.283rad/s^2

The sum of torque is:

\tau=I*\alpha

\tau=M*R^2/2*\alpha

\tau=0.060 N.m

8 0
3 years ago
What is the approximate uncertainty in the area of a circle of radius 4.5×10^4 cm? Express your answer using one significant fig
Igoryamba

Answer:

A=6.36\times 10^5\ m^2

Explanation:

It is given that,

Radius of the circle, r=4.5\times 10^4\ cm=4.5\times 10^2\ m

The area of the circle is given by :

A=\pi r^2

A=\pi (4.5\times 10^2\ m)^2

A=636172.51\ m^2

or

A=6.36\times 10^5\ m^2

As there is no uncertainty given in the radius of the circle. So, the area of the circle is 6.36\times 10^5\ m^2. Hence, this is the required solution.

5 0
3 years ago
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