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Gemiola [76]
3 years ago
6

A 1980-kg car is traveling with a speed of 15.5 m/s. What is the magnitude of the horizontal net force that is required to bring

the car to a halt in a distance of 39.2 m
Physics
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer: 6067.5 N

Explanation:

Work = Change in Energy. To start, all of the energy is kinetic energy, so find the total KE using: KE = 1/2(m)(v^2). Plug in 1980 kg for m and 15.5 m/s for v and get KE = 237847.5 J.

Now, plug this in for work: Work = Force * Distance; so, divide work by distance to get 6067.5 N.

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Examples of forces in motion that you can see?
lidiya [134]

Answer:

tensional force

Explanation:

It usually exist in fluid or any liquid substance where by an object is put before it

e.g An ant can walk on water without submersed in it.

6 0
3 years ago
What is cocanve mirror?​
pochemuha

Answer:

A mirror that has a reflecting surface that is recessed inward is called concave mirror

8 0
3 years ago
Read 2 more answers
A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm.
Orlov [11]

Complete question:

A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm. Find the number of moles of the gas.

Answer:

The number of mole of the gas is 0.164 mol.

Explanation:

Given;

volume of the ideal gas, V = 2.48 L

temperature of the gas, T = 0.964 °C = 273K + 0.964 = 273.964 K

pressure of the gas, P = 1.49 atm

The number of moles of the gas is calculated by using ideal gas equation;

PV = nRT

where;

n is the number of moles of the gas

R is ideal gas constant = 0.082057 L.atm/mol.K

n = \frac{PV}{RT} \\\\n = \frac{1.49 \ atm \ \times \ 2.48 \ L}{0.082057 \ L.atm/mol.K \ \ \times \ 273.964 \ K} \\\\n = 0.164 \ mol

Therefore, the number of mole of the gas is 0.164 mol.

6 0
3 years ago
The​ Eco-Marathon is an annual competition sponsored by Shell​ Oil, in which participants build special vehicles to achieve the
OverLord2011 [107]

Answer:

(1)  V=0.03348 gallons

(2)  L= 576.813 km .

Explanation:

Write the relation between the density and volume for ethanol.

density ( ρ )= m/V

Volume ( V )= m/ρ .......... (1)

Here, V is the volume of ethanol, m is the mass of ethanol, and  is the density of ethanol.

Write the relation between the specific gravity of ethanol and density of water

ρ=γ*ρ(water)  ............. (2)

Here,  is specific gravity of ethanol and  is the density of water.

Determine the volume of ethanol by substituting equation (2) in equation (1)

V=m/γ*ρ(water)

Substitute 100 gm , for m,  for , and 1000 kg/m  for.

V=\frac{100*10^{-3} }{0.789*1000}

V=0.000112674 m^{3

Convert m³ to gallons

V= (0.000112674*264.172 )

V=0.03348 gallons

Step 2:

Determine the distance travelled by the special vehicle named “Micro joule” runs with ethanol.

L=C*V    .......... (3)

Here,  is the rate of consumption of ethanol by Micro joule.

Substitute 10,705 mi/gallons  for C and 0.03348 gallons  for .

By using eq. 3.

L= 10750*0.03348

L=358.416 mi.

Convert the distance travelled by Micro joule from miles to kilometres

L= (358.416* 1.60934)

L = 576.813 km

Thus, the distance travelled by Micro joule is 576.813 km .

4 0
3 years ago
What is the acceleration?<br><br><br> –0.4 m/s2<br><br> –0.2 m/s2<br><br> 0.2 m/s2<br><br> 0.4 m/s2
denis23 [38]
We are asked to solve for the acceleration with the given graph in the problem. Let us recall that the formula for acceleration is shown below:
acceleration (a) = (Vf - Vi) / t
in this problem, we need to pick velocity final and initial such as:
Vf = 10 m/s
Vi = 8 m/s
Check the corresponding time, in this case, the time is (40seconds - 30seconds) equivalent to 10 seconds
Solving for the acceleration, we have it:
a = (10 - 8) / 10
a = 2/10
a = 0.2 m/s²

The answer is 0.2 m/s².
6 0
4 years ago
Read 2 more answers
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