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nevsk [136]
3 years ago
11

The sum of mike and Jordan’s age is 51. The difference in their ages is 17. If mike is older, what are the two men’s ages?

Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

Step-by-step explanation:

You can make equations.

M+J=51

M-J=17

Subtracting first equation from second equation:

2J=34

J=17 Jordan is 17

Therefore, Mike, is 34.

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A drawing is 12 inches wide and 10 inches long. Joe wants to enlarge each side by a scale factor of 0.3. What will be the area o
Andreyy89

Answer:

Area of the dilation = 10.8 square inches

Step-by-step explanation:

Given the original dimension

Length = 12inches

Width = 10inches

If they are dilated by a factor of 0.3

New length = 0.3 * 12 = 3.6in

New width = 0.3 * 10 = 3in

Area of the dilation = 3.6 * 3

Area of the dilation = 10.8 square inches

3 0
2 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
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Georgia [21]

Answer:

number 7: always bisect

3 0
3 years ago
Ayuda!!!!por favorrrrrrrrrrrrrrr
JulsSmile [24]

Answer:

z=24 y=5 x=12

Step-by-step explanation:

x+8=20  x=20-8 x=12

z+1=25 z=25-1 z=24

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3 years ago
Kara incorrectly factored 32x2 + 48x + 18 as shown. Describe her error and correctly factor the expression. 32x2 + 48x + 18 = 2(
aev [14]

Answer:

Kara incorrectly factored 2(16x^2 + 24x + 9) she did not find the correct factors when she factored out. The correct factored expression would be 2(4x+3)^2

Step-by-step explanation:

32x^2 + 48x + 18

2(16x^2 + 24x + 9)

2(16x^2 + 12x) (12x + 9)

2 4x(4x + 3) 3(4x + 3)

2(4x + 3)(4x + 3)

2(4x + 3)^2

3 0
3 years ago
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