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Ipatiy [6.2K]
3 years ago
9

A solution of a concentration of H+ (10-4 M) has a pH of​

Chemistry
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

pH = 4

Explanation:

pH = -log[H⁺] = -log(10⁻⁴) = -(-4) = 4

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An exothermic reaction has a positive enthalpy (heat) of reaction.(T/F)
mestny [16]

Answer:

True.

Explanation:

An exothermic reaction has a positive enthalpy (heat) of reaction. However, it can be negative in some circumstances.

5 0
3 years ago
Read 2 more answers
2 A certain gas of 25 g at 25°c and 0.65 atm occupies a volume of 23.52L Determine the molecule mass of the gas.​
denpristay [2]

Answer:

{ \bf{PV= \frac{m}{M} RT}} \\  \\ { \tt{(0.65  \times 23.52)  =  \frac{25}{M}  \times 0.081 \times (25 + 273)}} \\  \\ M = 39.5 \: g

8 0
3 years ago
Can you tell me name of Chemicals in food?​
Artyom0805 [142]

Answer:

Guar gum

sodium nitrite

artificial food colorings

monosodium glutamate

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6 0
2 years ago
A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

E^0_{[Cu^{2+}/Cu]}=+0.34V

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0
3 years ago
A 1500 kg race car accelerates at a rate of about 9M /s2 as to how much force does the engine need to create for this to happen
IgorC [24]

Answer:

13500 N

Explanation:

According to newtons second law of motion

mass m =1500 Kg

a = 9m/s^2

Force F = mass m × acceleration a

F = 1500×9= 13500 N

7 0
2 years ago
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