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eimsori [14]
3 years ago
10

Which of the following substances would show the smallest temperature change upon absorbing 2.35 kJ of heat? (MTS 2/10/2018) 27

g Fe ; cFe = 0.449 J/goC 27 g H2O ; cH2O = 4.18 J/goC 27 g ethanol ; cethanol = 2.42 J/goC
Chemistry
1 answer:
Darina [25.2K]3 years ago
7 0

Answer:

Water.

Explanation:

Hello,

Based on the formula:

Q=mCpΔT

Solving for ΔT, we state that:

Δ[tex]T=\frac{Q}{mCp}[/tex]

Now, for each substance we get:

ΔT_{Fe}=\frac{2350J}{27g*0.449J/g^0C} =193.85^0C\\

ΔT_{H_2O}=\frac{2350J}{27g*4.18J/g^0C} =20.82^0C\\

ΔT_{EtOH}=\frac{2350J}{27g*2.42J/g^0C} =35.97^0C\\

We sum up that the water shows the smallest temperature change. This could be also stated by know that the iron has the highest heat capacity.

Best regards.

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A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou
qwelly [4]

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = \frac{mass}{charge}

i.e Z = \frac{m}{Q} = \frac{0.225g}{1580C} = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ \frac{55}{valency} = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

8 0
3 years ago
How many moles are in 7.2x10^15 atoms of Pb?​
fiasKO [112]
<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

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Answer:

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