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galben [10]
4 years ago
12

Why does the entropy of a gas increase when it expands into a vacuum? Why does the entropy of a gas increase when it expands int

o a vacuum? The entropy of a gas increases when it expands into a vacuum because the number of possible states decreases . The entropy of a gas decreases when it expands into a vacuum because the number of possible states increases . The entropy of a gas increases when it expands into a vacuum because the number of possible states increases . The entropy of a gas decreases when it expands into a vacuum because the number of possible states decreases
Physics
1 answer:
Mrrafil [7]3 years ago
6 0

Answer:

The entropy of a gas increases when it expands into a vacuum because the number of possible states increases .

Explanation:

When a gas expand in a vacuum, the molecules of the gases vibrates very fast and starting moving with higher velocity in random directions which means the level of disorder in the gases increases.

Now the possible state of the gas molecule increases such as the particle can be located at different position due to increased randomness.

<u>Entropy is the measure of this randomness and thus with this increased randomness entropy also increases.</u>

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Which surface has the most friction? a An ice rink b A grassy field c A paved road
vovangra [49]

Answer:

An Ice Rink

Explanation:

7 0
3 years ago
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Will kilogram of hydrogen contains more atoms than kilogram of lead?
Zigmanuir [339]
Yes a kg of hydrogen will have more atoms than a kg of lead, because lead has a higher atomic mass, than hydrogen so it will take more atoms of hydrogen to make a kg than lead
4 0
4 years ago
What happens if :<br> . The test charge is not tiny.
docker41 [41]

The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

<h3>How does test charge affect electric field?</h3>

As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.

Adjusting the amount of charge on the test charge will not change the electric field force.

<h3>What is a test charge used for?</h3>

The charge that is used to measure the electric field strength is directed to as a test charge since it is used to test the field strength. The test charge has a portion of charge denoted by the symbol q.

To learn more about test charge, refer

brainly.com/question/16737526

#SPJ9

3 0
2 years ago
4. Which scientist proposed the theory that the Moon formed from fission? (5 points)
NeTakaya
The answer would be B, George Darwin :)
7 0
3 years ago
Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears a maximum sound intensity when sp
grandymaker [24]

Answer:

frequency of the sound = f = 1,030.3 Hz

phase difference = Φ = 229.09°

Explanation:

Step 1: Given data:

Xini = 0.540m

Xfin = 0.870m

v = 340m/s

Step 2: frequency of the sound (f)

f = v / λ

λ = Xfin - Xini = 0.870 - 0.540 = 0.33

f = 340 / 0.33

f = 1,030.3 Hz

Step 3: phase difference

phase difference = Φ

Φ = (2π/λ)*(Xini - λ) = (2π/0.33)* (0.540-0.33) = 19.04*0.21 = 3.9984

Φ = 3.9984 rad * (360°/2π rad)

Φ = 229.09°

Hope this helps!

5 0
3 years ago
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