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Gnesinka [82]
3 years ago
5

Daniel plans to have a garage sale. Research trends suggest that the best time to have a garage sale is before major U.S. holida

ys, when people are looking for discounted purchases. Based on scientific knowledge and trends, which of these would be the most favorable month for Daniel to have a garage sale?
Physics
1 answer:
miss Akunina [59]3 years ago
3 0

Complete question is;

Daniel plans to have a garage sale. Research trends suggest that the best time to have a garage sale is before major U.S. holidays, when people are looking for discounted purchases. Based on scientific knowledge and trends, which of these would be the most favorable month for Daniel to have a garage sale? April January July November

Answer:

November

Explanation:

We are told the best time to have a garage sale is before major US holidays.

Now, from the options given, the months that have the highest major US holidays are January and November.

January has New years day and Martin Luther King Jr's day. While November has veterans day and Thanksgiving day.

Now, the 2 months immediately after January has no major US holiday whereas, the 2 months after November have 2 major US holidays each.

Thus, the best option is November

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3 years ago
What is the acceleration caused by gravity of the planet Earth?
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The general accepted value of acceleration due to gravity, g, is 9.81 m/s^2.

That is an approximation because being the acceleration of gravity due to the attraction of the earth its magnitude will depend on the distance from the point to the center of the planet Earth.

The value of g is determined by using the Newton's Universal Law of gravity:

F = G * m of Earth * m of body / (distance^2)

Wehre {G* m of Earth / (distance^2) } = g

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Given the the Earth is not a perfect sphere the radius varies. Also the height of the body varies.

If you take a mean radius of Earth of 6.37*10^6 m

you get

g = 6.67*10^-11 N*m^2/kg^2 * 5.98*10^24kg / (6.37*10^6 m)^2 = 9.83 m/s^2

Again, if you want a more precise value of g, you need to find the exact place where you are and then use the right r.



 
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3 years ago
If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet
Shtirlitz [24]

The average distance between the planet and the star is:

R=9.36*10^11 m

Orbital velocity  v=√{(G*M)/R},

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M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

As was already said, Earth is located roughly 150 million kilometres (93 million miles) from the Sun on average. It is 1 AU. Mars is on our fictitious football field's three-yard line. On average, the distance between the Sun and the red planet is around 142 million miles (228 million kilometres).

Learn more about average distance:

brainly.com/question/18366547

#SPJ4

The complete question is ''If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 10^30 kg, what is the average distance between the planet and the star? 1.43 × 10^9 m 9.36 × 10^11 m 5.42 × 10^13 m 9.06 × 10^17 m''.

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1 year ago
An ocean liner leaves New York City and travels 18.0o north of east for 155 km. How far east and how far north has it gone? In o
Monica [59]
I’m sorry if i took up a lot of space, hope this is a valid approximate answer

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