Answer:
-2.66 kJ
Explanation:
At constant pressure, work done is:
W = -P ΔV
W = -(95.000 Pa) (43 m² − 15 m²)
W = -2660 J
W = -2.66 kJ
Given a steel rod:
Radius = r = 10 mm = 0.010 m.
Length L = 1 m.
Tensile Force = F = 100 kN.
Young's Modulus = Y = 2.0 &* 10¹¹ Nm⁻²
a) Stress = Force/cross sectional area
σ = F / A
= 100,000 /(π 0.010²) Pa
= 318.309 MPa
b) Y = (F/A) / (ΔL/L)
Elongation ΔL = L F / (A Y)
= L σ / Y
= 1 * 318.309 * 10⁶ / 2.0 * 10¹¹ m
= 1.591 mm
c) Percentage elongation : ΔL/L * 100 = 0.1591 %
It would be d and c hoped i helped!
Answer:
First law can be deduced from second law.
Acceleration may determine the position and velocity of the system.
Explanation:
When net force is zero, the second law is 0 = ma, or the motion is at constant speed. Thus first law establishes that when there are no forces, the object moves at constant speed, so first law is explained by using the second.
If you determine the acceleration of a system, you may use calculus or kinematic equations to determine velocity and position of the particle and determine how it moves. This is very important in mechanics and engineering, for example, for spacecrafts, forensic situations, etc.
