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3 years ago

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A student traveling at 8m/s on a bike has a mass of 182 KG and collides into a boulder and comes to a abrupt halt in 0.08 second

s. What is the magnitude of the average force acting on the car during the collision

1 answer:

Delicious77 [7]3 years ago

8 0

I hope this helps u !!

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What is the potential energy of a 2500 g object suspended 5 kg above the earth's surface?

Alinara [238K]

Answer:

$potential \: energy = mgh \\ = ( \frac{2500}{1000} ) \times 10 \times 5 \\ = 125 \: newtons$

if height is 5 m

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3 years ago

A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?

Bezzdna [24]

Answer:

Explanation: The initial velocity has two component v x and v y. The initial velocity in direction of y is given.

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3 years ago

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Which of the following activities works on muscle strength? A. cutting hedges B. moving furniture C. raking leaves D. vacuuming

Ksenya-84 [330]

The answer would be B

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3 years ago

Two bicycle tires are set rolling with the same initial speed of 3.30 m/s along a long, straight road, and the distance each tra

vredina [299]

Answer:

At low pressure- $\mu_{k}=0.02315$

At high pressure- $\mu_{k}=0.00445$

Explanation:

Initial speed, $V_{i}=3.3 m/s$

Final speed, $V_{f}=3.3/2= 1.65 m/s$

Net horizontal force due to rolling friction $F_{net}=\mu_{k}$ mg where m is mass, g is acceleration due to gravity, $\mu_{k}$ is coefficient of rolling friction

From kinematic relation, $V_{f}^{2}- V_{i}^{2}=2ad$

For each tire,

$V_{f}^{2}- V_{i}^{2}=2\mu_{k}gd$

Making $\mu_{k}$ the subject

$\mu_{k}=\frac {V_{f}^{2}- V_{i}^{2}}{2gd}$

Under low pressure of 40 Psi, d=18 m

$\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*18}=-0.02315$

Therefore, $\mu_{k}=0.02315$

At a pressure of 105 Psi, d=93.7

$\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*93.7}=-0.00445$

Therefore, $\mu_{k}=0.00445$

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3 years ago

How are newtons third law of motion applies to a system of objects

11111nata11111 [884]

Answer:

Newton's third law of motion states that whenever a first object exerts a force on a second object, the first object experiences a force equal in magnitude but opposite in direction to the force that it exerts. ... Newton's third law is useful for figuring out which forces are external to a system.

Explanation:

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3 years ago